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nikdorinn [45]
3 years ago
10

I need help finding the area of the shape.

Mathematics
1 answer:
fenix001 [56]3 years ago
4 0

Answer:

37.68 units²

Step-by-step explanation:

(3/4)(3.14)r²

(3/4)(3.14)(4²)

37.68

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Point t is on line segment su. Given st=6 and tu=5 determine the length of su
ch4aika [34]

Answer:

11 units

Step-by-step explanation:

Given that t is on the line su , then

su = st + tu = 6 + 5 = 11

6 0
2 years ago
Read 2 more answers
Match each expression to its value.
Klio2033 [76]
1) 7-5 = 2
2)-7+ 5 = -2
3) -7-5 = -12
4)7 - (-5) = 12

hope this helps! feel free to mark brainliest
3 0
3 years ago
Read 2 more answers
Find the missing length of the right triangle.
Luden [163]

Answer:

20...................

3 0
3 years ago
Geometry :))), please help me
amm1812

Answer:

x = -5

Step-by-step explanation:

Since these two triangles are similar, the ratio between the corresponding lengths of each triangle will be the same.

This means the ratio between one side of each triangle (e.g. AD and DC) will be the same as the ratio between a different side of each triangle (e.g. BE and BC).

So, to create an equation for the sides which contain the unknown 'x', we must first find the ratio between the two sides by using a different set of sides.

On the right side we are given 9 for AD, and 18 for DC.

9/18 = 0.5

This means that the extra length of the larger triangle from the smaller one (AD) is half the length of the smaller triangle (DC). We can use this to make an equation for x:

If AD/DC = 0.5, then BE/EC will also = 0.5

BE = x+23

EC = x+41

Therefore:

\frac{x+23}{x+41} = 0.5

Now we can solve by multiplying both sides by x+41 to eliminate the fraction:

x+23=0.5(x+41)

Now we multiply out the brackets and move the terms to different sides:

x+23=0.5x+20.5

0.5x = -2.5

x = -5

And if we substitute the -5 into the equations:

-5+23 = 18

-5 + 41 = 36

We will see that -5 does indeed give us the same ratio between the lengths:

18/36 = 0.5

Hope this helped!

4 0
3 years ago
Suppose f and g are continuous functions such that g(2) = 6 and lim x → 2 [3f(x) + f(x)g(x)] = 36. find f(2).
True [87]

Answer: f(2) = 4

Step-by-step explanation:

F(x) and g(x) are said to be continuous functions

Lim x=2 [3f(x) + f(x)g(x)] = 36

g(x) = 2

Limit x=2

[3f(2) + f(2)g(2)] = 36

[3f(2) + f(2) . 6] = 36

[3f(2) + 6f(2)] = 36

9f(2) = 36

Divide both sides by 9

f(2) = 36/9

f(2) = 4

7 0
3 years ago
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