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nexus9112 [7]
4 years ago
5

What is the slope of the line through the points (–3, 5) and (4, 5)?

Mathematics
2 answers:
attashe74 [19]4 years ago
7 0

The slope here is 0.

scoundrel [369]4 years ago
3 0

Answer:

slope = 0

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 3, 5) and (x₂, y₂ ) = (4, 5)

m = \frac{5-5}{4+3} = \frac{0}{7} = 0

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Read 2 more answers
Candy. Someone hands you a box of a dozen chocolate-covered candies, telling you that half are vanilla creams and the other half
BaLLatris [955]

Answer:

a) P=0.091

b) If there are half of each taste, picking 3 vainilla in a row has a rather improbable chance (9%), but it is still possible that there are 6 of each taste.

c) The probability of picking 4 vainilla in a row, if there are half of each taste, is P=0.030.

This is a very improbable case, so if this happens we would have reasons to think that there are more than half vainilla candies in the box.

Step-by-step explanation:

We can model this problem with the variable x: number of picked vainilla in a row, following a hypergeometric distribution:

P(x=k)=\dfrac{\binom{K}{k}\cdot \binom{N-K}{n-k}}{\binom{N}{n}}

being:

N is the population size (12 candies),

K is the number of success states in the population (6 vainilla candies),

n is the number of draws (3 in point a, 4 in point c),

k is the number of observed successes (3 in point a, 4 in point c),

a) We can calculate this as:

P(x=3)=\dfrac{\binom{6}{3}\cdot \binom{12-6}{3-3}}{\binom{12}{3}}=\dfrac{\binom{6}{3}\cdot \binom{6}{0}}{\binom{12}{3}}=\dfrac{20\cdot 1}{220}=0.091

b) If there are half of each taste, picking 3 vainilla in a row has a rather improbable chance (9%), but is possible.

c) In the case k=4, we have:

P(x=3)=\dfrac{\binom{6}{4}\cdot \binom{6}{0}}{\binom{12}{4}}=\dfrac{15\cdot 1}{495}=0.030

This is a very improbable case, so we would have reasons to think that there are more than half vainilla candies in the box.

4 0
3 years ago
A school receives a shipment of books. There are 60 cartons, and each carton weighs 42 pounds. The school's elevator can hold 22
Vladimir79 [104]
2200 divided by 42 = 52.
therefore 52 maximum number, with 8 in second load



7 0
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