gev me branly for the answer
Step-by-step explanation:
Answer:
a = $13.5
Step-by-step explanation:
Let a = adult tickets
Let c = children tickets
Translating the word problem into an algebraic equation;
<u>For the Martinez family;</u>
2a + 3c = $60
<u>For the Wright family;</u>
3a + 5c = $95.5
Thus, the simultaneous equations are;
..........equation 1
.........equation 2
We would use substitution method to solve;
From equation 2, we make a the subject of formula;
3a = 95.5 - 5c
a = (95.5 - 5c)/3
<em>Substituting the value of "a" into equation 1, we have;</em>
2[(95.5-5c)/3] + 3c = 60
Multiplying all through by 3;
2(95.5 - 5c) + 9c = 180
191 - 10c + 9c = 180
191 - c = 180
c = 191-180
c = $11
To find the value of a;
2a +3c = 60
<em>Substituting the value of "c" into the equation, we have;</em>
a = $13.5
<em>Therefore, the cost of an adult movie ticket is $13.5. </em>
<span>800 % = 8.00 or 800/100 or 8/1
800 is bigger than 100, so 8 would go before the decimal! </span>
Answer:
$21.25
Step-by-step explanation:
The cost of the 2 adult tickets before the discount is $8 * 2 = $16
The cost of the 2 child tickets before the discount is $5 * 2 = $10
The total cost before the discount is $16 + $10 = $26
The total cost after the discount is
$26 * (1 - 0.15) =
$26 * 0.85 =
$21.25