Now to solve this problem, we are given the number of atoms
therefore we must first convert this into number of moles. We can do this by
using the Avogadro’s number. Calculating for number of moles of Carbon:
number of moles Carbon = 21 atoms of carbon (1 mole / 6.022
x 10^23 atoms C)
number of moles Carbon = 3.49 x 10^-23 mol C
Converting this to mass by multiplying the molar mass of
C:
mass Carbon = 3.49 x 10^-23 mol C (12 g / mol)
mass Carbon = 4.18 x 10^-22 g
Therefore the mass of one molecule of Cortisone is:
mass of 1 molecule Cortisone = 4.18 x 10^-22 g / 0.6998
mass of 1 molecule Cortisone = 5.98 x 10^-22 g per molecule
Converting this to mass per 1 mol of Cortisone, by using
again the Avogadro’s number:
mass of 1 mol Cortisone = (5.98 x 10^-22 g / molecule) (<span>6.022
x 10^23 molecules / mol)</span>
mass of 1 mol Cortisone = 360.10 g / mol = molar mass of
cortisone
Answer:
360.10 g / mol
First one is a
the
second one is b
Answer:
there are elemental molecules, made from one type of atom (pure), example: oxygen and there are compound molecules, made from more then one type of atom, for example carbon dioxide
Answer:
C. copper.
Explanation:
- The atom which loses electrons (its oxidation sate be more positive) is the atom that is oxidized.
- While, the atom which gains electrons (its oxidation sate be more negative) is the atom that is reduced.
It is oxidation sate is changed from (+5) in the reactants (NO₃⁻) to (+4) in the products (NO₂). N gains 1 electron
So, it is reduced.
It is oxidation sate is the same (-2) in the reactants (NO₃⁻) and (-2) in the products (NO₂).
<em>So, it is neither be oxidized nor reduced.</em>
<em></em>
It is oxidation sate is changed (0) in the reactants (Cu) to (+2) in the products (Cu²⁺). Cu loses 2 electrons.
<em>So, it is oxidized.</em>
<em></em>
It is oxidation sate is the same (+1) in the reactants (H⁺) and (+1) in the products (H₂O).
<em>So, it is neither be oxidized nor reduced.</em>
<em></em>
