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aleksandrvk [35]
2 years ago
15

4 NH3 + 5 O2 --> 4 NO + 6 H2O

Chemistry
1 answer:
BigorU [14]2 years ago
6 0

Answer:

4 NH3+5 02. 4 NO + 6 H2O(g) will produced 1158 grm

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Please somebody help meeeeeeeeee
Whitepunk [10]

Answer:

C) The nucleus emits particles and/or energy

Explanation:

A key example of this is uranium, as when it decays it emits protons and neutrons, backing up our answer of C.

4 0
3 years ago
Maple syrup, which comes from the sap of maple trees, contains water and natural sugars. It's a clear, brown liquid and the suga
77julia77 [94]
Maple syrup, which comes from the sap of maple trees, contains water and natural sugars. It's a clear, brown liquid and the sugars can’t be separated by filtration. It should be categorized as a homogeneous mixture since the sugar is homogeneously dispersed<span> or mixed in water. It is completely dissolved resulting to uniform properties of the mixture.</span>
8 0
3 years ago
A sample of pure lithium carbonate contains 18.8% lithium by mass. What is the % lithium by mass in a sample of pure lithium car
VashaNatasha [74]

Answer:

There is 18.8% lithium by mass in second sample

Explanation:

Both the two samples are pure lithium carbonate. So % lithium by mass will be same in both samples. This can be proved mathematically as follows-

Let's assume weight of first sample is x g

So, 100 g of sample contains 18.8 g of lithium

Hence, x g of sample contains (\frac{18.8}{100}\times x) g of lithium

Now, the second sample has weight equal to 2x g

So, 2x g of sample contains (\frac{18.8}{100}\times 2x) g of lithium

So, % lithium by mass in second sample = (\frac{\frac{18.8}{100}\times 2x}{2x})\times 100 % = 18.8%

4 0
4 years ago
Which radioisotope undergoes beta decay and has a half-life of less than 1 minute?
erica [24]
N - 15 undergoes beta decay and has a half-life of less than 1 minute. 
7 0
4 years ago
How many grams of argon would it take to fill a large light bulb with a volume of 0.745 L at STP?
EastWind [94]

Answer:

Mass = 1.33 g

Explanation:

Given data:

Mass of argon required = ?

Volume of bulb = 0.745 L

Temperature and pressure = standard

Solution:

We will calculate the number of moles of argon first.

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

By putting values,

1 atm ×0.745 L = n × 0.0821 atm.L/mol.K× 273.15 K

0.745 atm. L = n × 22.43 atm.L/mol

n = 0.745 atm. L / 22.43 atm.L/mol

n = 0.0332 mol

Mass of argon:

Mass = number of moles × molar mass

Mass = 0.0332 mol × 39.95 g/mol

Mass = 1.33 g

8 0
3 years ago
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