Use the Pythagorean theorem since you are working with a right triangle:
a^2+b^2=c^2a2+b2=c2
The legs are a and b and the hypotenuse is c. The hypotenuse is always opposite the 90° angle. Insert the appropriate values:
0.8^2+0.6^2=c^20.82+0.62=c2
Solve for c. Simplify the exponents (x^2=x*xx2=x∗x ):
0.64+0.36=c^20.64+0.36=c2
Add:
1=c^21=c2
Isolate c. Find the square root of both sides:
\begin{gathered}\sqrt{1}=\sqrt{c^2}\\\\\sqrt{1}=c\end{gathered}1=c21=c
Simplify \sqrt{1}1 . Any root of 1 is 1:
c=c= ±11 *
c=1,-1c=1,−1
Answer:
Second table.
Step-by-step explanation:
A function has an additive rate of change if there is a constant difference between any two consecutive input and output values.
The additive rate of change is determined using the slope formula,
From the first table we can observe a constant difference of -6 among the y-values and a constant difference of 2 among the x-values.
For the second table there is a constant difference of 3 among the y-values and a constant difference of 1 among the x-values.
The additive rate of change of this table is
Therefore the second table has an additive rate of change of 3.
Answer:
D. 2
Step-by-step explanation:
M(0,2b)
N(2a,0)
Then the midpoint P coordinates are
P\left(\dfrac{2a+0}{2},\dfrac{0+2b}{2}\right)\Rightarrow P(a,b)
Use distance formula to find OP and MN:
OP=\sqrt{(a-0)^2+(b-0)^2}=\sqrt{a^2+b^2}\\ \\MN=\sqrt{(2a-0)^2+(2b-0)^2}=\sqrt{4a^2+4b^2}=2\sqrt{a^2+b^2}
So,
MN=2OP
or
OP=1/2 MN
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Coterminal angle is an angle which has the same initial and terminal side of the original angle. It can be found by adding or subtracting 360deg.
A positive angle less than 360 that is coterminal with -85 is = -85 + 360
= 275 degree
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