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3 years ago

14

Una carga positiva de 4 x 10-5 C, se encuentra a 0.05 m de otra carga positiva de 2 x 10-5 C. Calcular la fuerza que se ejerce e

ntre las dos cargas

1 answer:

KATRIN_1 [288]3 years ago

7 0

Answer:

La fuerza que se ejerce entre las dos cargas es 2880 N.

Explanation:

La ley de Coulomb indica que los cuerpos cargados sufren una fuerza atractiva o repulsiva al acercarse. La fuerza es atractiva si las cargas son del signo opuesto y repulsión si son del mismo signo. El valor de la fuerza es proporcional al producto del valor de sus cargas e inversamente proporcional al cuadrado de la distancia que los separa. Esto se expresa matemáticamente como:

$F=k*\frac{Q*q}{r^{2} }$

donde:

F es la fuerza eléctrica de atracción o repulsión. Se mide en Newtons (N).
Q y q son los valores de las dos cargas puntuales. Se miden en culombios (C).
r es el valor de la distancia que los separa. Se mide en metros (m).
k es una constante de proporcionalidad llamada constante de la ley de Coulomb.

En este caso:

F= ?
Q= 4*10⁻⁵ C
q= 2*10⁻⁵ C
r= 0.05 m
k= 9*10⁹ $\frac{N*m^{2} }{C^{2} }$

Reemplazando:

$F=9*10^{9} \frac{N*m^{2} }{C^{2} }*\frac{4*10^{-5} C*2*10^{-5}C }{(0.05 m)^{2} }$

F= 2880 N

<u><em>La fuerza que se ejerce entre las dos cargas es 2880 N.</em></u>

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