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aliya0001 [1]
3 years ago
7

What variables show a direct relationship? Check all that apply. the speed of a car and the distance traveled the elevation abov

e sea level and the air temperature the number of students in a cafeteria and the amount of food consumed the mass of an icicle and the time it takes to melt the distance a planet is from the Sun and that planet’s temperature the mass of a space shuttle and its acceleration through space
Physics
2 answers:
ZanzabumX [31]3 years ago
5 0
1, 3, and 4. I just took the quiz.
Llana [10]3 years ago
3 0
The variables that show a direct relationship are :
- The speed of a car and the distance traveled
- Number of students in  a cafeteria and the amount of food consumed
- The distance a planet is from the sun and that planet's temperature
- The mass of a space shuttle and its acceleration through space

In direct relationship, when one factor is increased/decreased , it will directly cause the other factor to be increased/decreased
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The part of the atom that carries no electric charge
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The answer is: A Neutron
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A balloon filled with helium gas at 1.00 atm occupies 15.6 L. Will the volume of the balloon increase or decrease in the upper a
Mariana [72]

Answer:

The volume of the balloon increases in the upper atmosphere.

Explanation:

p1= 1 atm

p2= 0.15 atm

V1= 15.6 L

V2= ?

p1*V1= p2 * V2

V2= (p1/p2)*V1

V2= 104 L

6 0
3 years ago
How is the acceleration of an object in newtons second law related to its mass and the net force on it?
9966 [12]
B) Acceleration is directly proportional to the mass of the object
4 0
3 years ago
Read 2 more answers
A 6.72 particle moves through a region of space where an electric field of magnitude 1270 N/C points in the positive direction,
Romashka [77]

Answer:

                    v_{y}  = -104 m/s

Explanation:

Using:

Force = electric field * charge

F=e*q

Force = magnitude of charge * velocity * magnetic field * sin tither

F_{x2}= |q|*v*B*sin \alpha

Force on particle due to electric field:

     F_{x1}= E*q = (1270N/C)*(-6.72*10^{-6} ) = -8.53*10^{-3}

Force on particle due to magnetic field:

F_{x2}= |q|*v*B*sin \alpha  = (6.72*10^{-6} )*(1.15)*(sin90)*v = (7.728*10^{-6})*(v)

F_{x2} is in the positive x direction as F_{x1} is in the negative x direction while net force is in the positive x direction.

Magnetic field is in the positive Z direction, net force is in the positive x direction.

According to right hand rule, Force acting on particle is perpendicular to the direction of magnetic field and velocity of particle. This would mean the force is along the y-axis. As this is a negatively charged particle, the direction of the velocity of the particle is reversed. Therefore velocity of particle, v, has to be in the negative y direction.

Now,

                    F_{xnet}- F_{x1 } = F_{x2 }

                    (6.13*10^{-3}) - (8.53*10^{-3} ) = (7.728*10^{-6})*(v)

                    v = (F_{xnet}  - F_{x1}) / (F_{x2} )

                        =((6.13*10^{-3} ) - (8.53*10^{-3})) / (7.728*10^{-6})

                       = (- 104.25) m/s

                      v_{y}  = -104 m/s

8 0
3 years ago
Neglecting air​ resistance, the distance s left parenthesis t right parenthesis in feet traveled by a freely falling object is g
ivann1987 [24]

Explanation:

It is given that, the height of a certain tower is 862 feet i.e to reach on the ground the object should travel, s = 862 feet

The distance traveled by a freely falling object is given by :

s(t)=16t^2

16t^2=862

t=\sqrt{53.875}

t = 7.34 seconds

So, the object will take 7.34 seconds to fall to the ground from the top of the​ building. Hence, this is the required solution.

7 0
3 years ago
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