A physics student is conducting an optical experiment using an Optical Bench Kit available in many physics classrooms. A lit can
1 answer:
You might be interested in
Answer:
4.0 m/s
Explanation:
The motion of the diver is the motion of a projectile: so we need to find the horizontal and the vertical component of the initial velocity.
Let's consider the horizontal motion first. This motion occurs with constant speed, so the distance covered in a time t is
where here we have
d = 3.0 m is the horizontal distance covered
vx is the horizontal velocity
t = 1.3 s is the duration of the fall
Solving for vx,
Now let's consider the vertical motion: this is an accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. The vertical position at time t is given by
where
h = 4.0 m is the initial height
vy is the initial vertical velocity
We know that at t = 1.3 s, the vertical position is zero: y = 0. Substituting these numbers, we can find vy
So now we can find the magnitude of the initial velocity:
Answer:
Explanation:
The equation that relates electric field strength and force that a charge experiments by it is F=qE.
Newton's 2nd Law states F=ma, which for our case will mean:
We know from accelerated motion that
In our case the proton is released from rest, so and we get
Substituting, we get our final velocity equation:
For the <em>proton </em>we know that and
. Writing in S.I. d=0.0025m, we obtain: