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EleoNora [17]
3 years ago
8

A physics student is conducting an optical experiment using an Optical Bench Kit available in many physics classrooms. A lit can

dle is positioned 20.cm from a concave mirror that produces an image 12cm from the mirror. Calculate the image position if the candle is repositioned 30.cm from the mirror. A. 5.Ocm B. 7.5cm C. 10.cm OD. 11cm E. 15cm
Physics
1 answer:
kobusy [5.1K]3 years ago
7 0

Answer:

C) 10 cm

Explanation:

We shall first calculate the focal length of the mirror.

object distance u = 20 cm ( negative )

Image distance v = 12 cm ( negative )

using mirror formula

1/ v + 1 /u = 1/ f

-1/12  - 1/ 20 =1/ f

f =- 7.5 cm

In the second case

u = - 30 cm

f = - 7.5 cm

i / v + 1 / u = 1 / f

1 / v - 1/30 = - 1/ 7.5

v = -10 cm

Answer is C that is 10 cm

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alexgriva [62]

C. 0.37V. A capacitor of 650x10⁻⁴F that stores 24x10⁻³C has a potential difference of 0.37V between its plates.

The key to solve this problem is using the capacitance equation C = Q/Vᵃᵇ, where C is the capacitance, Q the charge stored in the plates, and Vᵃᵇ the potential difference between the plates.

A 650x10⁻⁴F capacitor stores 24x10⁻³C, clear Vᵃᵇ for the equation:

C = Q/Vᵃᵇ -----------> Vᵃᵇ = Q/C

Solving

Vᵃᵇ = 24x10⁻³C/650x10⁻⁴F = 0.37V

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3 years ago
Newtons third law says that if Robert exerts a _______ of 1000 Newtons on an object, it will exert an equal and opposite _______
Free_Kalibri [48]

Answer: force, force

Explanation:

Newton’s third law states that there is an equal and opposite force

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3 years ago
1) You slam on the brakes of your car in a panic, and skid a certain distance on a straight level road. If you had been travelin
aleksandr82 [10.1K]

Answer:

d = 4 d₀o

Explanation:

We can solve this exercise using the relationship between work and the variation of kinetic energy

         W = ΔK

In that case as the car stops v_f = 0

the work is

          W = -fr d

we substitute

          - fr d₀ = 0 - ½ m v₀²

           d₀ = ½ m v₀² / fr

now they indicate that the vehicle is coming at twice the speed

          v = 2 v₀

using the same expressions we find

           d = ½ m (2v₀)² / fr

           d = 4 (½ m v₀² / fr)

           d = 4 d₀o

3 0
3 years ago
How long will it take a 2190 W motor to lift a 1.47 x 104 g box, 6.34 x 104 mm vertically.​
-BARSIC- [3]

Answer:

4.2s

Explanation:

Given parameters:

Power = 2190W

Mass of box = 1.47 x 10⁴g

distance  = 6.34 x 10⁴mm

Unknown:

Time  = ?

Solution:

Power is the rate at which work is done;

 Mathematically;

        Power  = \frac{work done}{time}  

   Time  = \frac{work done}{power}  

 Work done  = weight x height

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     100g = 1kg;

           1.47 x 10⁴g  = 14.7kg

convert the height to m;

          1000mm = 1m

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  Work done  = 14.7 x 9.8 x 63.4 = 9133.4J

  Time taken = \frac{9133.4}{2190}   = 4.2s

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