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EleoNora [17]
3 years ago
8

A physics student is conducting an optical experiment using an Optical Bench Kit available in many physics classrooms. A lit can

dle is positioned 20.cm from a concave mirror that produces an image 12cm from the mirror. Calculate the image position if the candle is repositioned 30.cm from the mirror. A. 5.Ocm B. 7.5cm C. 10.cm OD. 11cm E. 15cm
Physics
1 answer:
kobusy [5.1K]3 years ago
7 0

Answer:

C) 10 cm

Explanation:

We shall first calculate the focal length of the mirror.

object distance u = 20 cm ( negative )

Image distance v = 12 cm ( negative )

using mirror formula

1/ v + 1 /u = 1/ f

-1/12  - 1/ 20 =1/ f

f =- 7.5 cm

In the second case

u = - 30 cm

f = - 7.5 cm

i / v + 1 / u = 1 / f

1 / v - 1/30 = - 1/ 7.5

v = -10 cm

Answer is C that is 10 cm

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Answer:

b) using an indicator to measure the hydrogen ion concentration of a solution

6 0
4 years ago
Determine the speed of a falling object 7.8 sec after it dropped.
butalik [34]

Answer:

76.4m/s

Explanation:

Given parameter:

Time taken  = 7.8sec

Unknown:

Speed after it dropped  = ?

Solution:

To solve this problem, we use one of the kinematics equation:

      V  = U + gt

V is the final speed

U is the initial speed  = 0m/s

g is the acceleration due to gravity

t is the time taken

       V  = 0 + 9.8 x 7.8  = 76.4m/s

7 0
3 years ago
The eagle drops the trout a height of 6.1 m the fish travels 7.9 m horizontaly before hitting the water what is the velocity of
Semenov [28]

The velocity of the eagle is 7.0 m/s

Explanation:

The motion of the fish is a projectile motion, which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction, where the horizontal velocity of the fish is equal to the horizontal velocity of the eagle

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction  

We start by analyzing the vertical motion, using the following suvat equation:

s=ut+\frac{1}{2}at^2

where:

s = 6.1 m is the vertical displacement of the fish

u = 0 is the initial vertical velocity of the fish

a=g=9.8 m/s^2 is the acceleration of gravity

t is the time

Solving for t, we find the time of flight of the fish:

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(6.1)}{9.8}}=1.12 s

Now we know that during this time, the fish travels a horizontal distance of

x = 7.9 m

Therefore, the horizontal velocity of the fish is

v_x = \frac{x}{t}=\frac{7.9}{1.12}=7.0 m/s

And therefore, this is the initial velocity of the eagle.

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

6 0
4 years ago
A ball bounces changing velocity from vi=15m/s[D] to vf=15m/s[U] in t=0.01s. The balls acceleration is *
fomenos

Answer:

Option (A) is correct

Explanation:

a= (vf-vi)/ t

put the values

hence,

a= ( 15-15)/0.01

a=0

5 0
3 years ago
Read 2 more answers
Question C) needs to be answered, please help (physics)
Zarrin [17]

(a) Differentiate the position vector to get the velocity vector:

<em>r</em><em>(t)</em> = (3.00 m/s) <em>t</em> <em>i</em> - (4.00 m/s²) <em>t</em>² <em>j</em> + (2.00 m) <em>k</em>

<em>v</em><em>(t)</em> = d<em>r</em>/d<em>t</em> = (3.00 m/s) <em>i</em> - (8.00 m/s²) <em>t</em> <em>j</em>

<em></em>

(b) The velocity at <em>t</em> = 2.00 s is

<em>v</em> (2.00 s) = (3.00 m/s) <em>i</em> - (16.0 m/s) <em>j</em>

<em></em>

(c) Compute the electron's position at <em>t</em> = 2.00 s:

<em>r</em> (2.00 s) = (6.00 m) <em>i</em> - (16.0 m) <em>j</em> + (2.00 m) <em>k</em>

The electron's distance from the origin at <em>t</em> = 2.00 is the magnitude of this vector:

||<em>r</em> (2.00 s)|| = √((6.00 m)² + (-16.0 m)² + (2.00 m)²) = 2 √74 m ≈ 17.2 m

(d) In the <em>x</em>-<em>y</em> plane, the velocity vector at <em>t</em> = 2.00 s makes an angle <em>θ</em> with the positive <em>x</em>-axis such that

tan(<em>θ</em>) = (-16.0 m/s) / (3.00 m/s)   ==>   <em>θ</em> ≈ -79.4º

or an angle of about 360º + <em>θ</em> ≈ 281º in the counter-clockwise direction.

3 0
3 years ago
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