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svetlana [45]
3 years ago
8

80 timess 40 plus 60

Mathematics
2 answers:
jeka57 [31]3 years ago
3 0

Answer:

3260 hope i helped u

Step-by-step explanation:

Anika [276]3 years ago
3 0
80 times 40 is 320 then plus 60 equals 380 have a good rest of your day/night
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(x+2)^2 - (y+3)^2 factories this. Pls help me .​
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Answer:x^2−y^2+4x−6y−5

Step-by-step explanation:

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3 years ago
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A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

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3 years ago
Find the value of an exterior angle of a polygon with 12 sides​
Juli2301 [7.4K]

Answer:

\huge \boxed{30\°}

Step-by-step explanation:

To find the value of an exterior angle of a regular polygon, we can apply a formula.

\displaystyle \frac{360}{n}

n = \sf number \ of \ sides

\displaystyle \frac{360}{12}=30

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<span>A’(2, -4); B’(7, -9); C’(-2, -9)
I believe you did it correctly but over the wrong line. You were supposed to do it over line M and it looks like you did it over the X-axis.</span>
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3 years ago
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