Answer:
B. q = 2.5 x 10^-1 C
Explanation:
Formula: E = F/q
Given information:
E = 40 N/C
F = 10N
--> q = F/E = 10/40 = 0.25 C
or q = 2.5 x 10^-1 C
N*s... idk if you're anwser choices say 2.7N*s, but i had the exact question and this was the shown correct anwser.
Given:
= 323 K
= 293 K
specific heat of aluminium,
specific heat of water,
Formula Used:
Q = m
Solution:
Let the temperature at equilibrium be ' ' K
Now at equilibrium, using the given formula:
Temperature at equilibrium, = 295.513 K
Now, change in entropy(in J/K) is given by:
Q = m
= 12094.28 cal
Now,
= 40.93 cal/K = 9.78 J/K
Therefore change in entropy is given by: