The final atmospheric pressure is ![5.19\cdot 10^4 Pa](https://tex.z-dn.net/?f=5.19%5Ccdot%2010%5E4%20Pa)
Explanation:
Assuming that the temperature of the air does not change, we can use Boyle's law, which states that for a gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume. In formula,
![pV=const.](https://tex.z-dn.net/?f=pV%3Dconst.)
where
p is the gas pressure
V is the volume
The equation can also be rewritten as
![p_1 V_1 = p_2 V_2](https://tex.z-dn.net/?f=p_1%20V_1%20%3D%20p_2%20V_2)
where in our problem we have:
is the initial pressure (the atmospheric pressure at sea level)
is the initial volume
is the final pressure
is the final volume
Solving the equation for p2, we find the final pressure:
![p_2 = \frac{p_1 V_1}{V_2}=\frac{(1.01\cdot 10^5)(90.0)}{175.0}=5.19\cdot 10^4 Pa](https://tex.z-dn.net/?f=p_2%20%3D%20%5Cfrac%7Bp_1%20V_1%7D%7BV_2%7D%3D%5Cfrac%7B%281.01%5Ccdot%2010%5E5%29%2890.0%29%7D%7B175.0%7D%3D5.19%5Ccdot%2010%5E4%20Pa)
Learn more about ideal gases:
brainly.com/question/9321544
brainly.com/question/7316997
brainly.com/question/3658563
#LearnwithBrainly
Answer:
b) q large and m small
Explanation:
q is large and m is small
We'll express it as :
q > m
As we know the formula:
F = Eq
And we also know that :
F = Bqv
F = ![\frac{mv^{2} }{r}](https://tex.z-dn.net/?f=%5Cfrac%7Bmv%5E%7B2%7D%20%7D%7Br%7D)
Bqv = ![\frac{mv^{2} }{r}](https://tex.z-dn.net/?f=%5Cfrac%7Bmv%5E%7B2%7D%20%7D%7Br%7D)
or Eq = ![\frac{mv^{2} }{r}](https://tex.z-dn.net/?f=%5Cfrac%7Bmv%5E%7B2%7D%20%7D%7Br%7D)
Assume that you want a velocity selector that will allow particles of velocity v⃗ to pass straight through without deflection while also providing the best possible velocity resolution. You set the electric and magnetic fields to select the velocity v⃗ . To obtain the best possible velocity resolution (the narrowest distribution of velocities of the transmitted particles) you would want to use particles with q large and m small.
Streams carry sediment, like pebbles, in their flows. The pebbles can be in a variety of locations in the flow, depending on it's size, the balance between the upwards velocity on the pebble (drag and lift forces), and it's settling velocity.
Answer:
2.5 m/s
Explanation:
The speed of the animal is given by the ratio between the distance travelled by the animal and the time elapsed:
![v=\frac{d}{t}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%7D%7Bt%7D)
where d is the distance travelled and t the time elapsed. Note that this quantity is also equal to the slope of the curve.
In the time interval 0-20 s, we have
d = 50 m - 0 m = 50 m
t = 20 s - 0 s = 20 s
So, the speed is
![v=\frac{50 m}{20 s}=2.5 m/s](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B50%20m%7D%7B20%20s%7D%3D2.5%20m%2Fs)
Answer:
![a=0.2*10^{-5}g](https://tex.z-dn.net/?f=a%3D0.2%2A10%5E%7B-5%7Dg)
Explanation:
From the question we are told that:
Mass ![M=180=>0.18kg](https://tex.z-dn.net/?f=M%3D180%3D%3E0.18kg)
Charge ![Q=18mC=18*10^-^3C](https://tex.z-dn.net/?f=Q%3D18mC%3D18%2A10%5E-%5E3C)
Velocity ![v=2.2m/s](https://tex.z-dn.net/?f=v%3D2.2m%2Fs)
Length of Wire ![L=8.6cm=>0.086](https://tex.z-dn.net/?f=L%3D8.6cm%3D%3E0.086)
Current ![I=30A](https://tex.z-dn.net/?f=I%3D30A)
Generally the equation for Magnetic Field of Wire B is mathematically given by
![B=\frac{\mu_0*I}{2\pi*l}](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B%5Cmu_0%2AI%7D%7B2%5Cpi%2Al%7D)
![B=\frac{4*3.14*10^-^7*I}{2*3.14*8.6}](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B4%2A3.14%2A10%5E-%5E7%2AI%7D%7B2%2A3.14%2A8.6%7D)
![B=6.978*10^{-5}T](https://tex.z-dn.net/?f=B%3D6.978%2A10%5E%7B-5%7DT)
Generally the equation for Force on the plane F is mathematically given by
![F=qvB](https://tex.z-dn.net/?f=F%3DqvB)
Therefore
![ma=qvB](https://tex.z-dn.net/?f=ma%3DqvB)
![a=\frac{qvB}{m}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7BqvB%7D%7Bm%7D)
![a=\frac{18*10^{-5}83.4*6.978*10^{-5}}{0.18kg}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B18%2A10%5E%7B-5%7D83.4%2A6.978%2A10%5E%7B-5%7D%7D%7B0.18kg%7D)
![a=2.37*10^{-5}](https://tex.z-dn.net/?f=a%3D2.37%2A10%5E%7B-5%7D)
Therefore in Terms of g's
![a=\frac{2.37*10^{-5}}{9.8}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B2.37%2A10%5E%7B-5%7D%7D%7B9.8%7D)
![a=0.2*10^{-5}g](https://tex.z-dn.net/?f=a%3D0.2%2A10%5E%7B-5%7Dg)