Answer: 0.0594
Step-by-step explanation:
Given : The population proportion of adults questions reported that their health was excellent : p = 0.42
Among the 14 adults randomly selected from this area, only 3 reported that their health was excellent.
i.e. Sample size : n= 14


z-score : 
Put x= 3

Then, the probability that only 3 or fewer report having excellent health:-

Hence, the required probability : 0.0594
Answer:
7.1 weeks to 68.4 weeks
Step-by-step explanation:
Chebyshev's Theorem states that:
75% of the measures are within 2 standard deviations of the mean.
89% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 38.1
Standard deviation = 10.1
Between what two search times does Chebyshev's Theorem guarantee that we will find at least 89% of the graduates
Between 3 standard deviations of the mean.
So from 38.1 - 3*10.1 = 7.8 weeks to 38.1 + 3*10.1 = 68.4 weeks
The accumulated (future) value is given by the formula
F=P(1+i)^n
where
P=amount of deposit (made at the beginning of the first period)
i=monthly interest, APR/12 = 3%/12 =0.0025
n=number of periods (month)
For example, the future value for the 6th month is
F(6)=1000(1.0025^6)=1015.09 (to the nearest cent)
Here is a schedule of the values,
i=month
F(i) = value at the end of month i.
i F(i)
0 1000.0
1 1002.5
2 1005.01
3 1007.52
4 1010.04
5 1012.56
6 1015.09
7 1017.63
8 1020.18
9 1022.73
10 1025.28
11 1027.85
12 1030.42 + $50 deposit = 1050.42
All values are rounded to the nearest cent.
In the picture find 15 and 20 the answer for 16) 3/2= 150%
Answer:
20 happy to helPNMNJHUJN
Step-by-step explanation: