Answer:
How much heat energy required to convert following?
How much heat energy, in kilojoules, is required to convert 47.0 g of ice at -18.0 C to water at 25.0 C ?
Specific Heat of Ice - 2.09 j/g * c
This is how I did it and the answer is wrong...Please check and correct me
Q = m * Cice * Change in Temp
Q = (47.0 g)(2.09 J/g*c)(43) = 4222.6 J * 0.001 kj / j = 4.22 kj
Answer:
Your answer would be D) They both require a movement of charged particles
Explanation:
In short terms both the charge and the current are made up of charged particles that are always moving, they constantly move to well... stay charged, if they stopped, then the charge would fade until there is nothing left, and if there is nothing left -it means there would be no electricity to use
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Answer:
60-20=40km west because the direction Will favour whichever direction is bigger
Diffusion, facilitated diffusion, filtration, and osmosis
The rate constant of the second order reaction is 0.137 M-1s-1.
<h3>What is the rate constant?</h3>
For the second order reaction we can write;
1/[A] = kt + 1/[A]o
[A]o = initial concentration
[A] = final concentration
k = rate constant
t = time
Now;
1/0.319 = 13.5k + 1/ 0.740
1/0.319 - 1/0.740 = 13.5k
3.13 - 1.35 = 13k
k = 3.13 - 1.35/13
k = 0.137 M-1s-1
Learn more about second order reaction:brainly.com/question/12446045
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