Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
Here you go I hope I helped
Answer:
A
Step-by-step explanation:
Here, we want to get the number that will be in the units place
Six consecutive numbers from 33 are;
33 , 34 , 35 , 36 , 37 , 38 ,
Product of 5 and any of the even numbers will yield 0
That means the number on the unit place is 0
