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vagabundo [1.1K]
3 years ago
11

WILL GIVE A BRAINLEST!!!!!!

Mathematics
2 answers:
Andrej [43]3 years ago
5 0
We have that
<span>(c-4)/(c-2)=(c-2)/(c+2) - 1/(2-c)
 </span>- 1/(2-c)=-1/-(c-2)=1/(c-2)

(c-4)/(c-2)=(c-2)/(c+2)+ 1/(c-2)------- > (c-4)/(c-2)-1/(c-2)=(c-2)/(c+2) 
(c-4-1)/(c-2)=(c-2)/(c+2)---------------- > (c-5)/(c-2)=(c-2)/(c+2)

(c-5)/(c-2)=(c-2)/(c+2)------------- > remember (before simplifying) for the solution that c can not be 2 or -2
(c-5)*(c+2)=(c-2)*(c-2)------------------ > c²+2c-5c-10=c²-4c+4
-3c-10=-4c+4----------------------------- > -3c+4c=4+10----------- > c=14

the solution is c=14
 
the domain of the function is (-∞,-2) U (-2,2) U (2,∞) or 
<span>all real numbers except c=-2 and c=2</span>


jeka57 [31]3 years ago
5 0

The solution is c = 14

How many extraneous solutions are there? zero

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