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Kruka [31]
2 years ago
6

The figure shows the skeletal structure in line-angle (line-bond) mode of 2,5-dimethylhexa-1,4-diene. Identify the number of

Chemistry
1 answer:
deff fn [24]2 years ago
5 0

Answer:

There are 22 hydrogen in 2,3,3,5-tetramethylhexane (C10H22)

From the left to the right of the skeletal structure:

1st Main Carbon = 3 hydrogen

2nd Main Carbon = 1 hydrogen

1st Branch Carbon = 3 hydrogen

3rd Main Carbon = 2 hydrogen

2nd Branch Carbon = 3 hydrogen

3rd Branch Carbon = 3 hydrogen

4th Main Carbon = 0 hydrogen

4th Branch Carbon = 3 hydrogen

5th Main Carbon = 1 hydrogen

6th Main Carbon = 3 hydrogen

Total = 22 hydrogen

Explanation:

This is the skeletal formula for 2,3,3,5-tetramethylhexane - the 2D chemical structure. It is an organic compound. The carbon atoms in the structure are known as the carbon backbone. The hydrogen atoms are linked to the carbon backbone. This provides each carbon atom with four bonds.

Explanation:

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The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate
vovangra [49]

Answer:

K2 = 61.2 M^-1.S^-1

Explanation:

We complete the question fully:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0kJ/mol . If the rate constant of this reaction is 6.7M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

Answer is as follows:

The question asks us to calculate the value of the rate constant at a certain temperature, given that it is at a particular value for a particular temperature. We solve the question as follows:

According to Arrhenius equation, the relationship between temperature and activation energy is as follows:

            k = Ae^-(Ea/RT)

where,   k = rate constant

              A = pre-exponential factor

          Ea  = activation energy

             R = gas constant

              T = temperature in kelvin

From the equation, the following was derived for a double temperature problem:

ln(k2/k1) = (-Ea/R) * (1/T1 - 1/T2)

We list out the parameters as follows:

         

      T1= (244 + 273.15) K = 517.15 K

      T2= (324+ 273.15) K =597.15 K

    K1  = 6.7 ,     K2 = ?

         R = 8.314 J/mol K

     Ea = 71.0 kJ/mol = 71000 J/mol

Putting the given values into the above formula as follows:

ln(k2/6.7) = (-71000/8.314) * (1/517.15 - 1/597.15)

lnk2 - 1.902 = 8539.8 * 0.000259

lnK2 = 1.902 + 2.21

lnK2 = 4.114

K2 = e^(4.114)

K2 = 61.2

Hence, K2 = 61.2 (M.S)^-1

7 0
3 years ago
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Which conditions are necessary for natural selection? Check all that apply.
zepelin [54]

Answer:

Populations have genetic variation.

The environment changes.

Organisms must have specific traits in order to survive and reproduce.

Explanation:

Natural selection provides an advantage during an adverse condition for organisms that have a rich genetic variation in their population.

Also, environmental changes induced natural selection whereby organisms must adapt to changes around them.

For organisms to survive, they must have specific traits that gives them a competitive reproductive advantage.

3 0
2 years ago
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Calculate the density of a solid in g/cm3 if it weighs 38.3 kg and has a volume of 0.00463 m3.
RideAnS [48]

Answer: D=8.27 g/cm³

Explanation:

Density is mass/volume. Mass is in grams and volume is in liters. In this case, the problem wants our volume to be in cm³. All we need to do is to make some conversions to convert kg/m³ to g/cm³.

D=\frac{38.3kg}{0.00463m^3} *\frac{(1m)^3}{(100cm)^3} *\frac{1000g}{1kg}

With this equation, the m³ and kg cancel out, and we are left with g/cm³.

D=8.27 g/cm³

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3 years ago
Whats between -999 and 1000
Doss [256]
Hello!

Numbers from -998 and 999 are in between -999 and 1000.

I hope this was helpful! c:
7 0
3 years ago
Which of the following is not a chemistry topic?
Tju [1.3M]
I’m pretty sure it’s D
6 0
3 years ago
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