Answer:
C) Q < K, reaction will make more products
Explanation:
- 1/8 S8(s) + 3 F2(g) ↔ SF6(g)
∴ Kc = 0.425 = [ SF6 ] / [ F2 ]³
∴ Q = [ SF6 ] / [ F2 ]³
∴ [ SF6 ] = 2 mol/L
∴ [ F2 ] = 2 mol/L
⇒ Q = ( 2 ) / ( 2³)
⇒ Q = 0.25
⇒ Q < K, reaction will make more products
Answer:
Hydrogen
Explanation:
This may be wrong but I can't really tell because of how you have written the question
87.75 g of fructose
Explanation:
molar concentration = number of moles / volume (L)
number of moles = molar concentration × volume
number of moles of fructose = 1.5 × 0.325
number of moles of fructose = 0.4875 moles
number of moles = mass / molar weight
mass = number of moles × molar weight
mass of fructose = 0.4875 × 180
mass of fructose = 87.75 g
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molar concentration
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<span>Elements in Period 2 such as Barium and Beryllium can lose up to two electrons when they react, however Boron can lose up to three electrons when it reacts which causes it to break the pattern normally seen in Period 2.</span>
Answer: The vapor pressure of methanol solution at 298K is 107.12 torr
Explanation:
As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.
The formula for relative lowering of vapor pressure will be,
where,
= relative lowering in vapor pressure
i = Van'T Hoff factor = 1 (for non electrolytes)
= mole fraction of solute =
Given : 38.5 g of urea is present in 142 g of methanol
moles of solute (urea) = 
moles of solvent (methanol) = 
Total moles = moles of solute + moles of solvent = 0.64 + 4.4 = 5.04
= mole fraction of solute =
Thus the vapor pressure of methanol solution at 298K is 107.12 torr
