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kkurt [141]
3 years ago
5

What is the lcm of 5,3 and 5​

Mathematics
2 answers:
Bezzdna [24]3 years ago
6 0

Answer:

265

Step-by-step explanation:

im guessing you meant 53 instead of 5,3

icang [17]3 years ago
4 0

Answer:

the LCM of those would be 15.

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Find the ordered pairs for the x- and y-intercepts of the equation 3x − 2y = 18 and select the appropriate option below.
horsena [70]
Pretty sure the answer is B
8 0
3 years ago
which uppercase letters will not appear reversed when they are held in front of a mirror? what type of symmetry do these letters
Irina-Kira [14]
A,H,I,M,O,T,U,V,W,X,Y --- these have vertical symmetry

a word whose reflection is also a word....YAM and MAY 
3 0
3 years ago
34
Vadim26 [7]

Answer:

They are similar by the definition of similarity in terms of a dilation

Step-by-step explanation:

The given vertices of triangle ΔABC are;

A(1, 5), B(3, 9), and C(5, 3)

The vertices of triangle ΔDEF are;

D(-3, 3), E(-2, 5), and F(-1, 2)

Therefore, we get;

The length of segment, \overline{AB} = √((9 - 5)² + (3 - 1)²) = 2·√5

The length of segment, \overline{BC} = √((9 - 3)² + (3 - 5)²) = 2·√10

The length of segment, \overline{AC} = √((5 - 3)² + (1 - 5)²) = 2·√5

The length of segment, \overline{DE} = √((5 - 3)² + (-2 - (-3))²) = √5

The length of segment, \overline{EF} = √((2 - 5)² + (-1 - (-2))²) = √10

The length of segment, \overline{DF} = √((2 - 3)² + (-1 - (-3))²) = √5

∴ \overline{AB}/\overline{DE} = 2·√5/(√5) = 2

\overline{BC}/\overline{EF} = 2·√10/(√10) = 2

\overline{AC}/\overline{DF} = 2·√5/(√5) = 2

The ratio of their corresponding sides are equal and therefore;

ΔABC and ΔDEF are similar by the definition of similarity in terms of dilation.

4 0
3 years ago
the water level in a lake was monitored and was noted to have changed −2 1/3 inches in one year. The next year it was noted to h
Ket [755]
-3 1/2

just add the fractions


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5 0
3 years ago
Find the solution to the system 4x - y = -12 and -x - y = 3
nikdorinn [45]

Answer:

x = -3 , y = 0

Step-by-step explanation:

Solve the following system:

{4 x - y = -12 | (equation 1)

-x - y = 3 | (equation 2)

Add 1/4 × (equation 1) to equation 2:

{4 x - y = -12 | (equation 1)

0 x - (5 y)/4 = 0 | (equation 2)

Multiply equation 2 by 4/5:

{4 x - y = -12 | (equation 1)

0 x - y = 0 | (equation 2)

Multiply equation 2 by -1:

{4 x - y = -12 | (equation 1)

0 x+y = 0 | (equation 2)

Add equation 2 to equation 1:

{4 x+0 y = -12 | (equation 1)

0 x+y = 0 | (equation 2)

Divide equation 1 by 4:

{x+0 y = -3 | (equation 1)

0 x+y = 0 | (equation 2)

Collect results:

Answer: {x = -3 , y = 0

8 0
3 years ago
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