Using linear function concepts, it is found that:
- a) It costs $0.1 for each kilowatt hour of electricity used in excess of 250 kWh.
- b) f(90) = 46.6, which is the cost of 340 kWh of consumption in a month.
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A <em>linear function </em>has the format given by:
In which:
- m is the slope, which is the rate of change, that is, how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0.
The equation for the cost of h kilowatt hours (kWh) of electricity used in excess of 250 kWh is of:
Item a:
- The slope is of
, which means that it costs $0.1 for each kilowatt hour of electricity used in excess of 250 kWh.
Item b:
250 + 90 = 340.
f(90) = 46.6, which is the cost of 340 kWh of consumption in a month.
A similar problem is given at brainly.com/question/24808124
Answer:
The answer to your question is (x + 7)² + (y - 5)² = 88
Step-by-step explanation:
Equation
x² + 14x + y² - 10y = 14
Complete perfect trinomial squares
x² + 14x + (7)² + y² - 10y + (5)² = 14 + (7)² + (5)²
Simplify
x² + 14x + (7)² + y² - 10y + (5)² = 14 + 49 + 25
x² + 14x + (7)² + y² - 10y + (5)² = 88
Factor
(x + 7)² + (y - 5)² = 88 This is the equation in the form
center-radius
Answer:
Train A = 128
Train B = 68
Step-by-step explanation:
We can set up a system of equations for this problem
Let A = # of tons of Train A
Let B = # of tons of Train B
A + B = 196
A = B + 60
Now, we plug in A for the first equation, using substitution
(B+60) + B = 196
2B + 60 = 196
Subtract 60 from both sides
2B = 136
Divide both sides by 2
B = 68
Plug in 68 for B in the 2nd equation
A = 68 + 60
A = 128
Checking work: 128 + 68 = 196 :D hope this helped
30 is 50% of 60 because 50% is a half
Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
