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seropon [69]
3 years ago
12

Given the line q and r are parallel lines and m <3=123 find other angle measure

Mathematics
1 answer:
alekssr [168]3 years ago
7 0

.............................. us to be a good day at work and I don't know what to do it again and again and again and again and again and again and again and again

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If triangle ABC is dilated by a scale factor of 2.5 with a center of dilation at vertex B, how does the area of A'B'C' compare w
Dafna1 [17]
The area of A'B'C is 6.25 times the area of ABC. Also it wouldnt hurt the report the guy below who's obviously milking points.

6 0
3 years ago
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One half gallon is equivalent to 4 pints.how many gallons are the equivalent of 72 pints
malfutka [58]

Answer: 9 gallons

<u>Step-by-step explanation:</u>

Set up the proportion, then multiply to solve for the variable.

\dfrac{\frac{1}{2}\ \text{gallon}}{4\ \text{pints}}=\dfrac{x}{72\ \text{pints}}

(72\ \text{pints})\dfrac{\frac{1}{2}\ \text{gallon}}{4\ \text{pints}}=(72\ \text{pints)}\dfrac{x}{72\ \text{pints}}

\dfrac{36\ \text{gallons}}{4}=x}

9 gallons = x

5 0
4 years ago
A stereo store is offering a special price on a complete set ofcomponents (receiver, compact disc player, speakers, cassette dec
Korvikt [17]

Answer:

Step-by-step explanation:

(a)

The number of receivers is 5.

The number of CD players is 4.

The number of speakers is 3.

The number of cassettes is 4.

Select one receiver out of 5 receivers in 5C_1 ways.

Select one CD player out of 4 CD players in 4C_1 ways.

Select one speaker out of 3 speakers in 3C_1 ways.

Select one cassette out of 4 cassettes in 4C_1 ways.

Find the number of ways can one component of each type be selected.

By the multiplication rule, the number of possible ways can one component of each type be selected is,

The number of ways can one component of each type be selected is

=5C_1*4C_1*3C_1*4C_1\\\\=5*4*3*4\\\\=240

Part a

Therefore, the number of possible ways can one component of each type be selected is 240.

(b)

The number of Sony receivers is 1.

The number of Sony CD players is 1.

The number of speakers is 3.

The number of cassettes is 4.

Select one Sony receiver out of 1 Sony receivers in ways.

Select one Sony CD player out of 1 Sony CD players in ways.

Select one speaker out of 3 speakers in ways.

Select one cassette out of 4 cassettes in 4C_1 ways.

Find the number of ways can components be selected if both the receiver and the CD player are to be Sony.

By the multiplication rule, the number of possible ways can components be selected if both the receiver and the CD player are to be Sony is,

Number of ways can one components of each type be selected

=1C_1*1C_1*3C_1*4C_1\\\\=1*1*3*4\\\\=12

Therefore, the number of possible ways can components be selected if both the receiver and the CD player are to be Sony is 12.

(c)

The number of receivers without Sony is 4.

The number of CD players without Sony is 3.

The number of speakers without Sony is 3.

The number of cassettes without Sony is 3.

Select one receiver out of 4 receivers in 4C_1 ways.

Select one CD player out of 3 CD players in 3C_1 ways.

Select one speaker out of 3 speakers in 3C_1 ways.

Select one cassette out of 3 cassettes in 3C_1 ways.

Find the number of ways can components be selected if none is to be Sony.

By the multiplication rule, the number of ways can components be selected if none is to be Sony is,

=4C_1*3C_1*3C_1*3C_1\\\\=108

[excluding sony from each of the component]

Therefore, the number of ways can components be selected if none is to be Sony is 108.

(d)

The number of ways can a selection be made if at least one Sony component is to be included is,

= Total possible selections -Total possible selections without Sony

= 240-108

= 132  

Therefore, the number of ways can a selection be made if at least one Sony component is to be included is 132.

(e)

If someone flips the switches on the selection in a completely random fashion, the probability that the system selected contains at least one Sony component is,

= \text {Total possible selections with at least one Sony} /\text {Total possible selections}

= 132  / 240

= 0.55

The probability that the system selected contains exactly one Sony component is,

= \text {Total possible selections with exactly one Sony} /\text {Total possible selections}\frac{1C_1*3C_1*3C_1*3C_1+4C_11C_13C_13C_1+4C_13C_13C_13C_1}{240} \\\\=\frac{99}{240} \\\\=0.4125

Therefore, if someone flips the switches on the selection in a completely random fashion, then is the probability that the system selected contains at least one Sony component is 0.55.

If someone flips the switches on the selection in a completely random fashion, then is the probability that the system selected contains exactly one Sony component is 0.4125.

6 0
3 years ago
If a gardener fences in the total rectangular area shown in the illustration instead of just the square area, he will need twice
Norma-Jean [14]

Answer:

He needs 5x+56 ft

Step-by-step explanation:

To find how much of fencing he needs , we find the perimeter of the given figure

All sides are equal in a square

To find perimeter of the square we add all the sides

4 sides we have for the square

one side is x, so perimeter of square = x+x+x+x= 4x

Now we find perimeter of rectangle

Opposite sides of rectangle are equal

Here for rectangle we consider only three sides

because fourth side is common for rectangle and square

So perimeter of the rectangle (with 3 sides) = 28 +x+ 28 = 56+x

Total fencing = perimeter of square + perimeter of rectangle

4x + 56 + x= 5x+56


5 0
3 years ago
Help please?
Gennadij [26K]

Answer:

Step-by-step explanation:

with the largest measure

8 0
3 years ago
Read 2 more answers
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