<u>We'll assume the quadratic equation has real coefficients</u>
Answer:
<em>The other solution is x=1-8</em><em>i</em><em>.</em>
Step-by-step explanation:
<u>The Complex Conjugate Root Theorem</u>
if P(x) is a polynomial in x with <em>real coefficients</em>, and a + bi is a root of P(x) with a and b real numbers, then its complex conjugate a − bi is also a root of P(x).
The question does not specify if the quadratic equation has real coefficients, but we will assume that.
Given x=1+8i is one solution of the equation, the complex conjugate root theorem guarantees that the other solution must be x=1-8i.
Answer:
(2x+11)x (2x-11)
Step-by-step explanation:
Answer:
Step-by-step explanation:
8(1 + 2i) - (7 - 3i) = 8*1 + 8*2i + 7*(-1) - 3i*(-1)
= 8 + 16i -7 + 3i
= 8 - 7 + 16i + 3i
= 1 + 19i
Daniel forgot to multiply 2i by 8
Answer:
B=-2+5 collecting like terms
B=3 answer
