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tankabanditka [31]
3 years ago
11

What is the least common multiple (LCM) of 5 and 7 plz help need my grades up​

Mathematics
2 answers:
SSSSS [86.1K]3 years ago
5 0

Answer:

The least common multiple of 5 and 7 is 35

Step-by-step explanation:

Because 5 x 7 is 35

denis23 [38]3 years ago
5 0

Answer:

The Least common multiple ( LCM) of 5 and 7 is 35

Step-by-step explanation:

We list the first few multiples of 5 and 7a and identify the common multiples .

The least among the common multiples is the LCM of 5 and 7.

LCM 5 and 7

Multiples of 5: 5,10,15,20,25,30,35,40,45

Multiples of 7: 7,14,21,28,35,42,49

<u>The</u><u> </u><u>Least</u><u> </u><u>common</u><u> </u><u>multiple</u><u> </u><u>of</u><u> </u><u>5</u><u> </u><u>and</u><u> </u><u>7</u><u> is</u><u> </u><u>3</u><u>5</u><u> </u><u>.</u>

<u>l</u><u> </u><u>hope</u><u> </u><u>it</u><u> </u><u>helps</u><u> </u><u>❤</u><u>❤</u>

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WINSTONCH [101]

Answer:

30.5 ; 49 ; 27 ; 50 ; 45

Step-by-step explanation:

Determine the first and third quartiles. Determine the second decile and the eighth decile. Determine the 67th percentile

Given the ordered data :

13 13 13 20 26 27 29 32 34 34 35 35 36 37 38 41 41 41 42 44 46 47 48 50 53 55 56 62 67 82

Sample size, n = 30

The first quartile ;Q1

Q1 = 1/4(n+1)th term

Q1 = 31/4 = 7.75th term

Q1 = (29+32)/2

Q1 = 30.5

Q3 ;

Q3 = 3/4(n+1)th term

Q3 = 3(31)/4 = 23.25 th term

Q3 = (48 + 50) /2 = 49

2nd decile :

0.2 * (nth term

0.2 * 30 = 6th term = 27

8th decile :

0.8 * 30 = 24 th term

= 50

67th percentile :

0.67 * (n+1)th term

0.67 * 31 = 20.77

= (44 + 46) / 2

= 45

3 0
2 years ago
5A+10=200. Solve the problem
USPshnik [31]
Answer: A = 38

Steps:
5A = 200 - 10
5A = 190
A = 190/5
A = 38

I hope this helps :)
5 0
2 years ago
Read 2 more answers
*PLEASE ANSWER!!, I DONT GET IT*
Phoenix [80]

Answer:

b

Step-by-step explanation:

9 x 37 = 333

6 0
2 years ago
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10^2+12^2+14^2+......+26^2=??
Kazeer [188]

Answer:

3156

Step-by-step explanation:

  • <em>Used formula:</em>
  • <em>(1² + 2² + 3² + ... + n²) =1/6*n(n + 1)(2n + 1)</em>

--------

  • 10²+12²+14²+......+26² =
  • (2*5)²+(2*6)² + (2*7)² + ... + (2*13)² =
  • 4*(5²+6²+7²+...+13²) =
  • 4*(1²+2²+...+13² - (1²+2²+3²+4²)) =
  • 4*(1/6*13(13+1)(2*13+1) - (1+4+9+16)) =
  • 4*(1/6*13*14*27- 30) =
  • 4*(819 - 30) =
  • 4*789 =
  • 3156
3 0
3 years ago
Explain how the net of rectangular prism can help you find the surface area or the prism?
Aleksandr-060686 [28]

A 3d cardboard box has 6 sides, each of which are rectangles. If you unfold the 3D box, and flatten it out, then you'll be left with 6 rectangles such as what you see in the attachment below. This is one way to unfold the box. This flattened drawing is the net of the 3D rectangular prism. You can think of it as wrapping paper that covers the exterior of the box. There are no gaps or overlapping portions. If you can find the area of each piece of the net, and add up those pieces, that gets you the total area of the net. This is the exactly the surface area of the box.

In the drawing below, I've marked the sides as: top, bottom, left, right, front, back. This way you can see how the 3D box unfolds and how the sides correspond to one another. Other net configurations are possible.

7 0
3 years ago
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