Complete question is;
a. Two equal sized and shaped spheres are dropped from a tall building. Sphere 1 is hollow and has a mass of 1.0 kg. Sphere 2 is filled with lead and has a mass of 9.0 kg. If the terminal speed of Sphere 1 is 6.0 m/s, the terminal speed of Sphere 2 will be?
b. The cross sectional area of Sphere 2 is increased to 3 times the cross sectional area of Sphere 1. The masses remain 1.0 kg and 9.0 kg, The terminal speed (in m/s) of Sphere 2 will now be
Answer:
A) V_t = 18 m/s
B) V_t = 10.39 m/s
Explanation:
Formula for terminal speed is given by;
V_t = √(2mg/(DρA))
Where;
m is mass
g is acceleration due to gravity
D is drag coefficient
ρ is density
A is Area of object
A) Now, for sphere 1,we have;
m = 1 kg
V_t = 6 m/s
g = 9.81 m/s²
Now, making D the subject, we have;
D = 2mg/((V_t)²ρA))
D = (2 × 1 × 9.81)/(6² × ρA)
D = 0.545/(ρA)
For sphere 2, we have mass = 9 kg
Thus;
V_t = √[2 × 9 × 9.81/(0.545/(ρA) × ρA))]
V_t = 18 m/s
B) We are told that The cross sectional area of Sphere 2 is increased to 3 times the cross sectional area of Sphere 1.
Thus;
Area of sphere 2 = 3A
Thus;
V_t = √[2 × 9 × 9.81/(0.545/(ρA) × ρ × 3A))]
V_t = 10.39 m/s
Answer: 15.87 m
From the equation of motion:
where, 
is the distance traveled, 
is the initial velocity, 
is the acceleration and 
is the time.
The rock free falls under gravity. Initial velocity, 
, 
It took 
for rock to hit the water.
Substitute the values in the given equation:
Hence, the water is 15.87 m below the top level of the well.
Explanation:
To determine whether something is living or nonliving, a living thing must meet seven specific characteristics: feeding, movement, respiration, excretion, growth, sensitivity, and reproduction. A living organism needs to be able to feed to make energy and grow.
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Miss Hawaii
Answer:
voltage across = 1.6 V
Explanation:
given data
resistance R = 57.61 Ω
capacitance c = 13.13 mF = 13.13 ×
F
inductance L = 196.03 mH = 0.19603 H
fixed rms output Vrms = 23.86 V
to find out
voltage across circuit
solution
we know resonant frequency that is
resonant frequency = 1 / ( 2π√(LC)
put the value
resonant frequency = 1 / ( 2π√(0.19603×13.13 ×)
resonant frequency f = 3.1370 HZ
so current will be at this resonant is
current = Vrms / R
current = 23.86 / 57.61
current = 0.4141 A
and
so voltage across will be
voltage across = current / ( 2π f C )
voltage across = 0.4141 / ( 2π ( 3.1370) 13.13 × )
voltage across = 1.6 V
