Answer:
The acceleration is 8 m/s²
Explanation:
The given parameters are;
The initial velocity, u = 2 m/s
The final velocity, v = 6 m/s
The distance the acceleration took place, s = 2 m
The acceleration, a, can be found from the following kinematic equation;
v² = u² + 2·a·s
By substituting the values, we have;
6² = 2² + 2 × a × 2
6² - 2² = 2 × a × 2
32 = 4·a
a = 32/4 = 8 m/s²
The acceleration, a, of the given motion = 8 m/s².
Acceleration no longer exist as the car stops.
Assuming the friction between the skaters and the ice is negligible, the magnitude of Porsha's acceleration is 2.8m/s².
Missing part of the question: determine the magnitude of Porsha's acceleration.
Given the data in the question;
- Mass of Porsha;

- Mass of Zorn;

- Force of Porsha push;

Magnitude of Porsha's acceleration; 
To determine the magnitude of Porsha's acceleration, we use Newton's second laws of motion:

Where m is the mass of the object and a is the acceleration.
We substitute the mass of Porsha and the force he used into the equation
Therefore, assuming the friction between the skaters and the ice is negligible, the magnitude of Porsha's acceleration is 2.8m/s².
Learn more: brainly.com/question/25125444
They send out waves differently and cannot be heard easily