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Olegator [25]
3 years ago
5

If the car traveled 754 meters in a straight line between 0 and 36 seconds, what was the

Physics
1 answer:
ArbitrLikvidat [17]3 years ago
4 0

Answer:

20.94 m/s

Explanation:

Recall that average velocity is defined as:

V = distance / time

Then, for our case:

V = 754 m / 36 sec = 20.94 m/s

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You accelerate from 2m/s to 6m/s while traveling a distance of 2m; what was your acceleration?
nata0808 [166]

Answer:

The acceleration is 8 m/s²

Explanation:

The given parameters are;

The initial velocity, u = 2 m/s

The final velocity, v = 6 m/s

The distance the acceleration took place, s = 2 m

The acceleration, a, can be found from the following kinematic equation;

v² = u² + 2·a·s

By substituting the values, we have;

6² = 2² + 2 × a × 2

6² - 2² = 2 × a × 2

32 = 4·a

a = 32/4 = 8 m/s²

The acceleration, a, of the given motion = 8 m/s².

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PLEASE ASAP ILL GIVE BRAINLIEST.
Fiesta28 [93]
Acceleration no longer exist as the car stops.
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3 years ago
Zorn and Porsha are ice skating. Porsha has a mass of 60 kg, and Zorn has a mass of 40 kg. As they face each
algol13

Assuming the friction between the skaters and the ice is  negligible, the magnitude of Porsha's acceleration is 2.8m/s².

Missing part of the question: determine the magnitude of Porsha's acceleration.

Given the data in the question;

  • Mass of Porsha; m_{porsha} = 60kg
  • Mass of Zorn; m_{zorn} = 40kg
  • Force of Porsha push; F_{porsha} = 168N

Magnitude of Porsha's acceleration; a = \ ?

To determine the magnitude of Porsha's acceleration, we use Newton's second laws of motion:

F = m*a

Where m is the mass of the object and a is the acceleration.

We substitute the mass of Porsha and the force he used into the equation

168N = 60kg * a\\\\a = \frac{168kg.m/s^2}{60kg}\\\\a = 2.8m/s^2

Therefore, assuming the friction between the skaters and the ice is  negligible, the magnitude of Porsha's acceleration is 2.8m/s².

Learn more: brainly.com/question/25125444

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3 years ago
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