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3 years ago

How do i do this plzzzz help

Mathematics

2 answers:

erastovalidia [21]3 years ago

7 0

R=15

explain:
add the numbers in parentheses to get
45/3 = r
divide the numbers to get
15 = r

-Dominant- [34]3 years ago

4 0

(6+39)/3=?(r)

?(r)=15

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True or false: When moving to a bigger unit we divide or move our decimal to the left.

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2 years ago

Solve each equation. Check your solution.<br> 4t - 2 = 14

anyanavicka [17]

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2 years ago

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8. The trapezoids are similar. The area of the smaller trapezoid is 131 m2. Find the area of the larger trapezoid to the nearest

kolbaska11 [484]

Answer:

$3,726\ m^{2}$

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor

Let

z----> the scale factor

x----> corresponding side of the larger trapezoid

y----> corresponding side of the smaller trapezoid

$z=\frac{x}{y}$

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substitute

$z=\frac{64}{12}$

step 2

Find the area of the larger trapezoid

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z----> the scale factor

x----> area of the larger trapezoid

y----> area of the smaller trapezoid

$z^{2}=\frac{x}{y}$

we have

$z=\frac{64}{12}$

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$(\frac{64}{12})^{2}=\frac{x}{131}$

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3 years ago

Which word sentence represents the equation 4y = y + 9 ?

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3 years ago

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PLEASE HELP ME!!!!!!!!!!!!!!!!!!

lilavasa [31]

Answer:

a) 4 - $vt - d = \frac{1}{2} at^{2}$

b) 1 - $2(vt - d) = at^{2}$

c) 6 - $\frac{2(vt - d)}{t^{2}} = a$

Step-by-step explanation:

It simply asks the steps to go from the original displacement formula to isolate a (the acceleration). It's just a matter of moving items around.

We start with:

$d = vt - \frac{1}{2} at^{2}$

We then move the vt part on the left side, then multiply each side by -1 (to get rid of the negative on the at side and to match answer choice #4):

$vt - d = \frac{1}{2} at^{2}$

Then we multiply each side by 2 to get rid of the 1/2, answer #1:

$2(vt - d) = at^{2}$

Finally, we divide each side by t^2 to isolate a (answer #6):

$\frac{2(vt - d)}{t^{2}} = a$

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3 years ago