Question

I need help with this physics question.

Answer 1

The acceleration will increase by 61.3%.

Explanation:

The centripetal acceleration $a_c$ is given by

$a_c = \dfrac{v^2}{r}$

If the velocity of the object increases by 27.0%, then its new velocity v' becomes

$v' = 1.270v$

The new centripetal acceleration $a'_c$ becomes

$a'_c = \dfrac{(1.270v)^2}{r} = 1.613 \left(\dfrac{v^2}{r} \right)$

$\:\:\:\:\:\:\:\:\:= 1.613a_c$