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pishuonlain [190]
3 years ago
11

In facts about Plastics, Explorer how the economy (the way materials are made, sold, and bought) is affected by using and produc

ing plastics. Use the information to answer the question.
How does producing plastics benefit economy? PLEASE HELP ME WRITE A PARAGRAPH PLEASE AND THANK U
Physics
2 answers:
umka2103 [35]3 years ago
8 0
<h2>Plastic Benefits Economy </h2>

Producing plastics benefit economy in various ways. We can assist preserve the extra energy by the process of recycling in the making of plastic items. Plastics are utilized for making mobile phones, T.V, computers, and many other items. The items which are being used by plastic is very beneficial in this way, plastics provide much benefit to our economy.

Our economy runs through the items for various purposes which are made by plastics. They are present in the buildings like in walls, fans, lights and many other items. There are many items made of plastic that are found in homes which provides advantages to our economy compared to other material made products.    

Mandarinka [93]3 years ago
4 0

Producing plastics benefits the economy by employing workers and helps the economy of every state by spending billions of dollars on shipping plastic products.

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A counterflow double-pipe heat exchanger is used to heat water from 20°C to 80°C at a rate of 1.2 kg/s. The heating is to be com
bixtya [17]

Answer:L=109.16 m

Explanation:

Given

initial temperature =20^{\circ}C

Final Temperature =80^{\circ}C

mass flow rate of cold fluid \dot{m_c}=1.2 kg/s

Initial Geothermal water temperature T_h_i=160^{\circ}C

Let final Temperature be T

mass flow rate of geothermal water \dot{m_h}=2 kg/s

diameter of inner wall d_i=1.5 cm

U_{overall}=640 W/m^2K

specific heat of water c=4.18 kJ/kg-K

balancing energy

Heat lost by hot fluid=heat gained by cold Fluid

\dot{m_c}c(T_h_i-T_h_e)= \dot{m_h}c(80-20)

2\times (160-T)=1.2\times (80-20)

160-T=36

T=124^{\circ}C

As heat exchanger is counter flow therefore

\Delta T_1=160-80=80^{\circ}C

\Delta T_2=124-20=104^{\circ}C

LMTD=\frac{\Delta T_1-\Delta T_2}{\ln (\frac{\Delta T_1}{\Delta T_2})}

LMTD=\frac{80-104}{\ln \frac{80}{104}}

LMTD=91.49^{\circ}C

heat lost or gain by Fluid is equal to heat transfer in the heat exchanger

\dot{m_c}c(80-20)=U\cdot A\cdot (LMTD)

A=\frac{1.2\times 4.184\times 1000\times 60}{640\times 91.49}=5.144 m^2

A=\pi DL=5.144

L=\frac{5.144}{\pi \times 0.015}

L=109.16 m

6 0
3 years ago
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