Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.20×10^6 N, one at an angle 14.0∘ west of north,
and the other at an angle 14.0∘ east of north, as they pull the tanker a distance 0.750 km toward the north. What is the total work they do on the supertanker?
1 answer:
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Answer:
The minimum speed of the box bottom of the incline so that it will reach the skier is 8.19 m/s.
Explanation:
It is given that,
Mass of the box, m = 2.2 kg
The box is inclined at an angle of 30 degrees
Vertical distance, d = 3.1 m
The coefficient of friction,
Using the work energy theorem, the loss of kinetic energy is equal to the sum of gain in potential energy and the work done against friction.
W is the work done by the friction.
v = 8.19 m/s
So, the speed of the box is 8.19 m/s. Hence, this is the required solution.
Answer:
is the minimum gap between the slabs
Explanation:
Given:
- length of the concrete highway,
- coefficient of thermal expansion,
- range of temperature variation,
<u>Now form the equation of thermal expansion:</u>
Since each slab of the highway expands by the above length so the minimum gap between the slabs to prevent buckling:
is the minimum gap between the slabs