Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.20×10^6 N, one at an angle 14.0∘ west of north,
and the other at an angle 14.0∘ east of north, as they pull the tanker a distance 0.750 km toward the north. What is the total work they do on the supertanker?
1 answer:
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Answer : The correct option is (d) 2.73 m
Explanation :
By the 2nd equation of motion,
where,
s = distance or height = ?
u = initial velocity = 3.0 m/s
t = time = 0.5 s
a = acceleration due to gravity =
Now put all the given values in the above equation, we get:
Therefore, the correct option is (d) 2.73 m
Answer:
5.565 V
Explanation:
Radius of coil of generator=r=0.14 m
Length of wire=l=10 m
Magnetic field,B=0.24 T
Angular speed,
We have to find the peak emf of the generator.
Peak(maximum) induced emf of generator=
Using the formula
Velocity:
Velocity is change in displacement with respect to time:
Analysing the units, meters (displacement) and seconds (time) are basic units:
Therefore the unit of velocity is m/s
Force:
Newton's second law of motion:
Kilogram (mass) is a basic unit, and accelerations unit can be found using the equation:
Analysing the units:
Therefore, the unit of force is:
Pressure:
Pressure is given by the equation:
where S is area of effect, F is force
Area for a basic rectangle (geometric shape is arbitrary for dimensional analysis) is found by multiplying two lengths:
, the unit of area
Dividing the aforementioned unit of force by the unit of area:
, the unit of pressure
Work:
Work is given by the equation:
, (dot product may be assumed as normal multiplication for the purposes of unit analysis)
Knowing displacement's (x) unit is m:
, the unit of work.