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Tasya [4]
3 years ago
7

How much work (in J) is required to expand the volume of a pump from 0.0 L to 2.7 L against an external pressure of 1.0 atm?

Physics
1 answer:
spin [16.1K]3 years ago
5 0

Answer:

-2.79 x 10²J

Explanation:

using the pressure volume work formula which states that

work = -PΔV

           = -(1.0 atm) (2.7-0.0)L = -2.7L . atm

Convert litre.atmosphere to Joules.

1 L . atm = 101.325 joules

-2.75 L .atm = -2.75 x 101.325 = -278.64375 =

Work = -2.79 x 10²J

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So, there should be two forces acting on the refrigerator: the applied force and the friction force.

The question mentioned that the friction force was set to zero, so the only effective force now would be the applied force.

We have an applied force of 400 N to the right, this means that:
<span>The magnitude of the net force is 400, directed to the right.</span>
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3 years ago
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1. What is the kinetic energy of a 94 kg basketball player running at 7.3 m/s?
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1. 2504.63 J

2. 929.5m/s

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Acceleration increases over time once a force is applied to the object. Given a force of 10.0 Newtons, which mass will have the
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Mass is indirectly proportional to acceleration, so, lighter the object greater would be it's acceleration...

A) 0.10 kg is lightest among them, so it's your answer

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One end of an insulated metal rod is maintained at 100 ∘C and the other end is maintained at 0.00 ∘C by an ice–water mixture. Th
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Answer:

k=105.0359\times 10^4\,W.m^{-1}.K^{-1}

Explanation:

Given:

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temperature at the cooler end, T_C=0^{\circ}C

length of rod through which the heat travels, dx=0.7\,m

cross-sectional area of rod, A=1.1\times 10^{-4}\,cm^2

mass of ice melted at zero degree Celsius, m=8.7\times 10^{-3}\,kg

time taken for the melting of ice, t=15\times60=900\,s

thermal conductivity k=?

By Fourier's Law of conduction we have:

\dot{Q}=k.A.\frac{dT}{dx}......................................(1)

where:

\dot{Q}=rate of heat transfer

dT= temperature difference across the length dx

Now, we need the total heat transfer according to the condition:

we know the latent heat of fusion of ice,  L = 334000\,J.kg^{-1}

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Q=8.7\times 10^{-3}\times 334000

Q=2905.8\,J

Now the heat rate:

\dot{Q}=\frac{Q}{t}

\dot{Q}=\frac{2905.8}{900}

\dot{Q}=3.2287\,W

Now using eq,(1)

3.2287=k\times 1.1\times 10^{-4} \times \frac{100}{0.7}

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8 0
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What type of force is needed for motion to occur?
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