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Tasya [4]
3 years ago
7

How much work (in J) is required to expand the volume of a pump from 0.0 L to 2.7 L against an external pressure of 1.0 atm?

Physics
1 answer:
spin [16.1K]3 years ago
5 0

Answer:

-2.79 x 10²J

Explanation:

using the pressure volume work formula which states that

work = -PΔV

           = -(1.0 atm) (2.7-0.0)L = -2.7L . atm

Convert litre.atmosphere to Joules.

1 L . atm = 101.325 joules

-2.75 L .atm = -2.75 x 101.325 = -278.64375 =

Work = -2.79 x 10²J

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ra1l [238]

Answer:

a) t = 4.16 s

b) x = 141.51 m

Explanation:

Given

v = 21.5 m/s

x0 = 52.0 m

a = 6.0 m/s²

a) Motorcycle

x = v0*t + (a*t²/2)

x = 21.5t + (6*t²/2)

x = 21.5t + 3t²   <em>(I)</em>

Car

x = x0 + v0*t

x = 52 + 21.5t  <em>(II)</em>

<em />

then we can apply <em>I = II</em>

21.5t + 3t² = 52 + 21.5t

⇒ 3t² = 52

⇒ t = 4.16 s

b) We can use <em>I</em> or <em>II</em>, then

x = 52 + 21.5*(4.16)

⇒ x = 141.51 m

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Answer:

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