<span>1 mole of calcium carbonate reacts with 1 mole of sulfuric acid and produces 1 mole of calcium sulfate.
3.1660 g of CaCO3 is how many moles of calcium carbonate? 3.1660 / 100.0869 = 0.031633 moles.
3.2900 g of H2S04 is how many moles of sulfuric acid? 3.2900 / 98.079 = 0.033544 moles.
</span><span>The lesser of the two is 0.031633 moles.
Therefore, 0.031633 moles of calcium carbonate will combine with 0.031633 moles of sulfuric acid to produce 0.031633 moles of calcium sulfate.
Molecular weight of calcium sulfate is 136.14 g/mol.
Therefore, 0.031633 moles of calcium sulfate will weight 0.031633 x 136.14 g/mol = 4.3065 grams.</span>
Answer:
33.38g of NaCl are produced
0.03338kg of NaCl are produced
Explanation:
The reaction of sodium hydroxide, NaOH, and hydrogen chloride, HCl, occurs as follows:
NaOH + HCl → NaCl + H₂O
To find mass of NaCl produced we need to determine the moles of water produced. As when 1 mole of water is produced, 1 mole of NaCl is also produced we can find moles of NaCl and its mass, thus:
<em>Moles H₂O -Molar mass: 18.015g/mol-</em>
10.29g * (1mol / 18.015g) = 0.5712 moles H₂O = 0.5712 moles NaCl
Now, the mass of NaCl -Molar mass: 58.44g/mol- is:
0.5712 moles NaCl * (58.44g / mol) =
<h3>33.38g of NaCl are produced</h3><h3>0.03338kg of NaCl are produced</h3>
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