Answer:
23.0 s⁻¹ is rate constant
Explanation:
Using the Arrhenius equation:
k = A * e^(-Ea/RT)
Where k is rate constant
A is frequency factor (1.5x10¹¹s⁻¹)
Ea is activation energy = 55800J/mol
R is gas constant (8.314J/molK)
And T is absolute temperature (24°C + 273 = 297K)
Replacing:
k = 1.5x10¹¹s⁻¹ * e^(-55800J/mol/8.314J/molK*297K)
k = 1.5x10¹¹s⁻¹ * 1.53x10⁻¹⁰
k = 23.0 s⁻¹ is rate constant i hope this helpsss
Explanation:
Answer:
The type of reaction for the following equation is combustion equation.
Explanation:
Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.

The reaction given to us:

When 1 mole of ethane reacts with 7/2 moles of oxygen gas it gives 3 moles of water and 2 moles of carbon dioxide gas.
The type of reaction for the following equation is combustion equation.
Answer:
The answer to this is
The column of water in meters that can be supported by standard atmospheric pressure is 10.336 meters
Explanation:
To solve this we first list out the variables thus
Density of the water = 1.00 g/mL =1000 kg/m³
density of mercury = 13.6 g/mL = 13600 kg/m³
Standard atmospheric pressure = 760 mmHg or 101.325 kilopascals
Therefore from the equation for denstity we have
Density = mass/volume
Pressure = Force/Area and for a column of water, pressure = Density × gravity×height
Therefore where standard atmospheric pressure = 760 mmHg we have for Standard tmospheric pressure= 13600 kg/m³ × 9.81 m/s² × 0.76 m = 101396.16 Pa
This value of pressure should be supported by the column of water as follows
Pressure = 101396.16 Pa = kg/m³×9.81 m/s² ×h
∴
= 10.336 meters
The column of water in meters that can be supported by standard atmospheric pressure is 10.336 meters