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3 years ago

The environment with the greatest biodiversity is the one with the greatest variety of

Chemistry

1 answer:

ValentinkaMS [17]3 years ago

5 0

Answer: species

Explanation:

The biodiversity can be defined as variety of life form in a area concerned or in all the parts of the world. The environment with the greatest biodiversity will have the greatest variety of species. Each species will boost the productivity of the ecosystem as each species has a roe to be played in an ecosystem. For example, a larger number of plant species will result in greater variety of crops. The higher species diversity will ensure the sustainability of all life forms in an ecosystem.

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Carbon based life forms

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If you need to measure the volume of liquid in a bottle of eyedrops, what unit would be the most practical?

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The most practical would be milliliters

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For the following unbalanced equation: Cu(s) + AgNO₃(aq) ➞ Cu(NO₃)₂(aq) + Ag(s) if 1.50 moles of copper and 3.00 moles of silver

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2 years ago

You have 100 mL of a solution of benzoic acid in water; the amount of benzoic acid in the solution is estimated to be about 0.30

dimaraw [331]

Answer:

0.00370 g

Explanation:

From the given information:

To determine the amount of acid remaining using the formula: $\dfrac{(final \ mass \ of \ solute)_{water}}{(initial \ mass \ of \ solute )_{water}} = (\dfrac{v_2}{v_1+v_2\times k_d})^n$

where;

v_1 = volume of organic solvent = 20-mL

n = numbers of extractions = 4

v_2 = actual volume of water = 100-mL

k_d = distribution coefficient = 10

∴

$\dfrac{(final \ mass \ of \ solute)_{water}}{0.30 \ g} = (\dfrac{100 \ ml}{100 \ ml +20 \ ml \times 10})^4$

$\dfrac{(final \ mass \ of \ solute)_{water}}{0.30 \ g} = (\dfrac{100 \ ml}{100 \ ml +200 \ ml})^4$

$\dfrac{(final \ mass \ of \ solute)_{water}}{0.30 \ g} = (\dfrac{1}{3})^4$

$\dfrac{(final \ mass \ of \ solute)_{water}}{0.30 \ g} = 0.012345$

Thus, the final amount of acid left in the water = 0.012345 * 0.30

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3 years ago

I. Give the name for the following compounds:

alexandr402 [8]

Answer:

Explanation:

1) MgBr₂

Magnesium bromide

2) Ca₃(PO₄)₂

Calcium phosphate

3) NO₂

Nitrogen dioxide

4) Ni₂(CO₃)₃

Nickel(III) carbonate

5) (NH₄)₂CO₃

Ammonium carbonate

6) MnBr₂

Manganese bromide

7) Na[MnO₄]

Sodium permanganate

8) P₂O₅

Phosphorus pentoxide

9) CCl₄

Carbon tetrachloride

10) Fe(OH)₂

Iron(ii) hydroxide

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2 years ago