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FinnZ [79.3K]
2 years ago
7

Which evidence supports the claim that matter can bend light waves?

Chemistry
2 answers:
solmaris [256]2 years ago
8 0

Answer:d

Explanation:I’m not 100% sure how to explain it but I’m almost for sure it’s d.

pantera1 [17]2 years ago
8 0

Answer:

D

Explanation:

I think it would be D. Refraction is an example of matter (being water) bending light as it travels through another medium (from air)

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Complete the following equations (note that the equations are not balanced). Use the act
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Answer:

Explanation:

a

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A sample of Br 2 ( g ) Br2(g) takes 42.0 min 42.0 min to effuse through a membrane. How long would it take the same number of mo
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15 mins

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6 0
3 years ago
Be sure to answer all parts. Write the balanced equations corresponding to the following rate expressions: a) rate = − 1 3 Δ[CH4
Alinara [238K]

Answer : The balanced equations will be:

(a) 3CH_4+2H_2O+CO_2\rightarrow 4CH_3OH

(b) 2N_2O_5\rightarrow 2N_2+5O_2

(c) 2H_2+2CO_2+O_2\rightarrow 2H_2CO_3

Explanation :

The general rate of reaction is,

aA+bB\rightarrow cC+dD

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}

\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}

\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}

\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}

Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

Now we have to determine the balanced equations corresponding to the following rate expressions.

(a) Rate=-\frac{1}{3}\frac{d[CH_4]}{dt}=-\frac{1}{2}\frac{d[H_2O]}{dt}=-\frac{d[CO_2]}{dt}=+\frac{1}{4}\frac{d[CH_3OH]}{dt}

The balanced equations will be:

3CH_4+2H_2O+CO_2\rightarrow 4CH_3OH

(b) Rate=-\frac{1}{2}\frac{d[N_2O_5]}{dt}=+\frac{1}{2}\frac{d[N_2]}{dt}=+\frac{1}{5}\frac{d[O_2]}{dt}

The balanced equations will be:

2N_2O_5\rightarrow 2N_2+5O_2

(c) Rate=-\frac{1}{2}\frac{d[H_2]}{dt}=-\frac{1}{2}\frac{d[CO_2]}{dt}=-\frac{d[O_2]}{dt}=+\frac{1}{2}\frac{d[H_2CO_3]}{dt}

The balanced equations will be:

2H_2+2CO_2+O_2\rightarrow 2H_2CO_3

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Since this is Argon it would be a noble gas
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Don't use the brakes too hard when u stop. That can cause the biker to fall forward.

Give me a thanks if it helps!!
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