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hichkok12 [17]
3 years ago
10

1 airplane

Physics
1 answer:
Nana76 [90]3 years ago
3 0

Answer:

Explanation:

Speed is scalar and velocity is vector. Vector values imply direction as well as magnitude. Therefore, speed and velocity are not the same. The speeds of these 2 planes are the same at 300km/hr, but the velocity of the plane traveling north is +300km/hr while the velocity of the plane traveling south is -300km/hr if we define north as positive and south as negative.

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When a projectile reaches the highest point the vertical component of the acceleration is:
Mazyrski [523]

Answer:

The acceleration is g.

Taking the upward direction as positive

V = Vy y - 1/2 g t^2

Taking the downward direction as positive

V = -V y + 1/2 g t^2

One can choose either direction as positive, but the acceleration is

the same as g (it is g) while the projectile is in the air.

6 0
3 years ago
You recently purchased a home four blocks from the busy tollway. On a typical evening, the decibel level resulting from tollway
inn [45]

Answer:

74dB

Explanation:

Sound intensity is inversely proportional to the square of the distance. Thus, a house four times closer hears a sound 16x more intense.

The dB scale is logarithmic, so 16x louder than 62 dB is equal to

62 + 10*log(16) ~= 62 + 12 = 74dB

5 0
3 years ago
Show which of the following functional forms work or do not work as solutions to this differential equation (known as 'the wave
Akimi4 [234]

Answer:

E = A cos (Bx + Ct) and E = A cos (Bx + Ct + D)

Explanation:

The wave equation is

           d²y / dx² = 1 /v²  d²y / dt²

Where v is the speed of the wave

Let's review the solutions

In this case y = E

a) E = A sin Bt

 This cannot be a solution because the part in x is missing

      dE / dx = 0

b) E = A cos (Bt + c)

There is no solution missing the Part in x

         dE / dx = 0

c) E = A x² t²

The parts are fine, but this solution is not an oscillating wave, so it is not an acceptable solution of the wave equation

d) E = A cos (Bx + Ct) and E = A cos (Bx + Ct + D)

Both are very similar

Let's make the derivatives

       dE / dx = -A B sin (Bx + Ct + D)

      d²E / dx² = -A B² cos (Bx + Ct + D)

      dE / dt = - A C sin (Bx + Ct + D)

      d²E / dt² = -A C² cos (Bx + Ct + D)

We substitute in the wave equation

      -A B² cos (Bx + Ct + D) = 1 / v² (-A C² cos (Bx + Ct + D))

       B² = 1 / v² (C²)

       v² = (C / B)²

       v = C / B

We see that the two equations can be a solution to the wave equation, the last one is the slightly more general solution

8 0
3 years ago
What was the velocity of the ball at 10 seconds?
ANTONII [103]

Answer:

if your talking about the velocity after the ball falls, it would be -100m/s

Explanation:

7 0
3 years ago
In an old-fashioned amusement park ride, passengers stand inside a 3.0-m-tall, 5.0-m-diameter hollow steel cylinder with their b
Ksivusya [100]

Answer:

\omega = 2.56 rad/s

Explanation:

As the cylinder rotates the centripetal force on all the passengers is due to normal force due to the wall

So here we can say

N = m\omega^2 R

now when floor is removed all the passengers are safe because here friction force on the passenger is counter balanced by the weight of the passengers

so we can say

F_f = mg

\mu_s F_n = mg

\mu_s (m\omega^2 R) = mg

\mu_s \omega^2 R = g

\omega = \sqrt{\frac{g}{\mu_s R}}

for minimum rotational speed we have

\omega = \sqrt{\frac{9.8}{0.60(2.5)}

\omega = 2.56 rad/s

8 0
3 years ago
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