Answer:
The speed of space station floor is 49.49 m/s.
Explanation:
Given that,
Mass of astronaut = 56 kg
Radius = 250 m
We need to calculate the speed of space station floor
Using centripetal force and newton's second law
Where, v = speed of space station floor
r = radius
g = acceleration due to gravity
Put the value into the formula
Hence, The speed of space station floor is 49.49 m/s.
Answer:
The deceleration is
Explanation:
From the question we are told that
The distance of the car from the crossing is
The speed is
The reaction time of the engineer is
Generally the distance covered during the reaction time is
=>
=>
Generally distance of the car from the crossing after the engineer reacts is
=>
=>
Generally from kinematic equation
Here v is the final velocity of the car which is 0 m/s
So
=>