Because the masses that you give are for blocks that are 1 cubic meter in volume, they also serve as the densities for the two metals that you are comparing.
<span>mass = density*volume </span>
<span>volume = (4/3)*pi*r^3 </span>
<span>volume of iron sphere = (4/3)*3.14*0.0201^3 = 3.40*10^-5 m^3 </span>
<span>mass of iron sphere = 7860* 3.40*10^-5 m^3 = 0.27 kg = mass of Aluminum Sphere </span>
<span>Volume of Al Sphere = 0.27/2700 = 9.90*10^-5 m^3 </span>
<span>Radius = cube root (volume / (4/3) / pi) = 2.87 cm. </span>
<span>I did this using the MS calculator, and I'm not 100% sure on the numerical answer, but the process is what you need to do to solve the problem. You should double check my answer.
hope this helped :)
</span>
The pressure exerted by this force is equal to 320 
.
<u>Given the following data:</u>
- Area = 25
.
To calculate the pressure exerted by this force:
<h3>How to calculate pressure.</h3>
Mathematically, pressure is given by this formula:
<u>Where:</u>
Substituting the given parameters into the formula, we have:
P = 320 .
Read more on pressure here: brainly.com/question/8033367
This is just a simple problem finding out the outer surface charge, the inner surface charge and the net charge. Net charge by definition means the difference between two charges. In this case, the formula that is applicable here is outer surface charge = total net charge - inner cavity surface charge. Since we are given already with the net charge equal to 12.0 x10-6 C and the inner charge magnituude f 3.7 x10-6 C, the the total charge must be outer charge is +10x10(-6)) - (-3.0x10(-6)) = +1.3x10(-5) C.
Charges are measured in coloumbs and most likely exist on surfaces of entities like particles, walls etc.
<h2>
Answer:</h2>
800gm
<h2>
Explanation:</h2>
Archimedes principle states that when an object is immersed in a liquid there is an apparent loss of weight of the object. This apparent loss of weight is also the upthrust experienced by the liquid. The upthrust is equal to the weight of the liquid displaced.
Following from the above statement, when the body of volume 100c.c is immersed in the water contained in the jar, the upthrust experienced is equal to the weight of the water displaced.
<em>Note: In the question, weight is measured just using the mass.</em>
Mass (m) is the product of density (ρ) of liquid (which is water in this case) and volume (v) of body immersed. i.e
m = ρ x v
Where;
ρ = 1 gm/cm³
v = 100c.c = 100cm³
=> m = 1 gm/cm³ x 100cm³
=> m = 100gm
Therefore the weight of water displaced is 100gm
Now, the weight of the water and jar after immersion is the sum of the weight of water and jar before immersion, and the weight of the water displaced. i.e
Weight of water and jar after immersion = 700gm + 100gm = 800gm
