Question

Write an equation of a line with slope -3/2 and x-intercept (4,0)

Answer 1

Answer:

An equation of a line with slope -3/2 and x-intercept (4,0) will be:

$y\:=\:-\frac{3}{2}x\:+\:6$

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

• m is the slope

• b is the y-intercept

Given

• Slope m = -3/2

• x-intercept (4, 0)

now substitute m = -3/2 and the point (4, 0) in the slope-intercept form of line equation

$y = mx+b$

$0\:=\:-\frac{3}{2}\left(4\right)\:+\:b\:\:\:\:\:$

$-6+b=0$

Add 6 to both sides

$-6+b+6=0+6$

Simplify

$b=6$

Thus, the y-intercept b = 6

now substitute m = -3/2 and b = 6  in the slope-intercept form of line equation

$y = mx+b$

$y\:=\:-\frac{3}{2}x\:+\:6$

Therefore, an equation of a line with slope -3/2 and x-intercept (4,0) will be:

$y\:=\:-\frac{3}{2}x\:+\:6$