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Serhud [2]
3 years ago
8

A characteristic used to describe something is called a

Chemistry
2 answers:
Pani-rosa [81]3 years ago
3 0
Trait-descriptive adjectives.



adjectives that can be used to describe characteristics of people are called.
patriot [66]3 years ago
3 0
Character trait i think
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The number at the end of an isotope's name is the number
Korolek [52]

Answer:

Atomic neutron mass electron number

Explanation:

7 0
3 years ago
A 59.1g sample of aluminum is put into a calorimeter (see sketch at right) that contains 250.0g of water. The aluminum sample st
Rainbow [258]

Answer:

The specific heat capacity of aluminum according to this experiment is 0.863 J/g°C

Explanation:

Step 1: Data given

Mass of aluminium = 59.1 grams

Mass of water = 250.0 grams

Initial temperature of aluminium = 91.3 °C

Initial temperature of water = 16.0 °C

Final temperature = 19.5 °C

Pressure remains constant

Specific heat capacity of water = 4.186 J/g°C

Step 2: Calculate specific heat of aluminium

Heat lost = heat gained

Qlost = -Q heat

Q = m*c*ΔT

heat aluminium = - heat water

m(aluminium) * c(aluminium) * ΔT(aluminium) = -m(water) * c(water) * ΔT(water)

⇒m(aluminium) = mass of aluminium = 59.1 grams

⇒c(aluminium) = the specific heat of aluminium = TO BE DETERMINED

⇒ΔT = the change in temperature = T2 -T2 = 19.5 - 91.3 = -71.8 °C

⇒ m(water) = 250.0 grams

⇒c(water) = the specific heat of water = 4.186 J/g°C

⇒ΔT = the change in temperature = T2 -T2 = 19.5 - 16.0 = 3.5 °C

59.1 * c(aluminium) * -71.8 °C = 250.0 * 4.186 J/g°C * 3.5 °C

c(aluminium) = 0.863 J/g°C

The specific heat capacity of aluminum according to this experiment is 0.863 J/g°C

3 0
3 years ago
Binary Covalent (molecular) Compounds
prisoha [69]

Answer:

why is ur name different sexxxy............................................................

Explanation:

5 0
2 years ago
Which compound forms from 2 parts of hydrogen and 1 part of oxygen?
lina2011 [118]
Water, H2O, HOH these are all the same compound just worded differently
6 0
3 years ago
Number of moles in 31.99g O2 <br> And 176.8g NaCl
sergey [27]

#O_2

\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:mass}{Molar\:mass}

\\ \sf\longmapsto No\:of\:moles=\dfrac{31.99}{32}

\\ \sf\longmapsto No\:of\:moles\approx 1

#NaCl

\\ \sf\longmapsto No\:of\:moles=\dfrac{176.8}{58.5}

\\ \sf\longmapsto No\;of\:moles=3mol

8 0
2 years ago
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