Draw the structure of 2 methyl,but-3-ene
1 answer:
Answer:
Please find the structure attached as an image
Explanation:
Based on the characteristics ending name (-ene) of the organic compound above, it belongs to the ALKENE GROUP. Alkenes are characterized by the possession of a carbon to carbon double bond (C=C) in their structure.
- But-3-ene tells us that the organic compound has four straight carbon atoms with the C=C (double bond) located on the THIRD carbon depending on if we count from right to left or vice versa.
- 2 methyl indicates that the methyl group (-CH3) is located as an attachment on the second carbon (carbon 2).
N.B: In the structure attached below, the counting is from the left to right (→).
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Answer:
C) 4.24 x
Explanation:
E = Δm
Δm = 0.0284 x 1.66 x kg = 4.714x
kg
putting value in above equation
E = 4.714xkg x (3x
= 4.24 x
Answer:
Percentage dissociated = 0.41%
Explanation:
The chemical equation for the reaction is:
The ICE table is then shown as:
Initial (M) 1.8 0 0
Change (M) - x + x + x
Equilibrium (M) (1.8 -x) x x
where ;
Since the value for is infinitesimally small; then 1.8 - x ≅ 1.8
Then;
Dissociated form of 4-chlorobutanoic acid =
Percentage dissociated =
Percentage dissociated =
Percentage dissociated = 0.4096
Percentage dissociated = 0.41% (to two significant digits)