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2 years ago

Calculate the moles and grams of solute in each solution. D. 2.0 L of 0.30M Na2SO4. I already have A, B, and C. Thanks!

Chemistry

2 answers:

Sindrei [870]2 years ago

8 0

D. Is the correct answer

e-lub [12.9K]2 years ago

4 0

Find the number of moles
C = n / V
C(Concentration) = 0.30 moles / L
V ( Volume) = 2 L
n = ??
n = C * V
n = 0.30 mol / L * 2 L
n = 0.60 mol

Find the molar mass
2Na = 23 * 2 = 46 grams
1S = 32 * 1 = 32 grams
O4 = 16 * 4 = 64 grams
Total = 142 grams / mol

Find the mass
n = given mass / molar mass
n = 0.06 mol
molar Mass = 142 grams / mol
given mass = ???

given mass = molar mass * mols
given mass = 142 * 0.6
given mass = 85.2 grams.

85.2 are in a 2 L solution that has a concentration of 0.6 mol/L

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100.0 g of 4.0°C water is heated until its temperature is 37.0°C. If the specific heat of water is 4.184 J/g°C, calculate the am

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Answer:

13.8072 kj

Explanation:

Given data:

Mass of water = 100.0 g

Initial temperature = 4.0 °C

Final temperature = 37.0°C

Specific heat capacity = 4.184 j/g.°C

Heat absorbed = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

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ΔT = 37.0°C - 4.0 °C

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3 years ago

2. A solvent used in cleaning is found to contain only the elements carbon, hydrogen, and chlorine. When a

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mass of C = 0.238 g

mass of H =0.00989 g

mass of Cl = 1.05 g

Explanation:

Determine the masses of carbon, hydrogen, and chlorine in the original sample of the solvent.

First we need to calculate the molar mass of carbon dioxide (CO₂) and water (H₂O)

molar mass of CO₂ = molar mass of C × 1 + molar mass of O × 2

molar mass of CO₂ = 12 × 1 + 16 × 2 = 44 g/mole

molar mass of H₂O = molar mass of H × 2 + molar mass of O × 1

molar mass of H₂O = 1 × 2 + 16 × 1 = 18 g/mole

Now, to find the mass of carbon and hydrogen in the original sample of solvent, we devise the following reasoning:

if 44 g of CO₂ contains 12 g of C

then 0.872 g of CO₂ contains X g of C

X = (0.872 × 12) / 44 = 0.238 g of C

if 18 g of H₂O contains 2 g of H

then 0.089 g of H₂O contains Y g of H

Y = (0.089 × 2) / 18 = 0.00989 g of H

And now, we can find the mass of chlorine:

mass of sample = mass of C + mass of H + mass of Cl

mass of Cl = mass of sample - mass of C - mass of H

mass of Cl = 1.30 - 0.238 - 0.00989

mass of Cl = 1.05 g

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3 years ago

The density of mercury, the only metal to exist as a liquid at room temperature, is 13.6 g/cm3. What is that density in pounds p

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Answer:

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From Density of Mercury (13.6g/cm3) given,

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Volume = 1cm3

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2.54 cm = 1 in

1cm = 1/2.54 = 0.394in

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Density = Mass /volume

Density = 0.03lb/0.061 in^3

Density = 0.492 lb/in^3

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