Answer:
B) 125 m
Explanation:
Thermodynamic Processes
1 answer:
Answer:
A. Part a is the attachment
B. total work = 10.4kj
Explanation:
T1 = constant temperature
nRT1 = PaVa = PbVb
We write equation as
5ma = Pa, 5L = Va, Vb = 10L(temperature is doubled)
W1 = 25 ln2
W1 = 25 x 0.693
= 17.327kj
The isochoric expansion has no change in volume. So,
W2 = 0
Isothermal compression
T3 = constant temperature
nRT3 = PcVc = PdVd
Pc = 1mpa Vc = 10L Vd = 5L
= 10x-0.693
= -6.93kj
Isochoric compression has no change in volume. Workdone w4 = 0
Total workdone = w1 + w2 + w3 + w4
= 17.33 + 0 + (-6.93) + 0
= 10.4kj
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Here mass of the iron pan is given as 1 kg
now let say its specific heat capacity is given as "s"
also its temperature rise is given from 20 degree C to 250 degree C
so heat required to change its temperature will be given as
now if we give same amount of heat to another pan of greater specific heat
so let say the specific heat of another pan is s'
now the increase in temperature of another pan will be given as
now we have
now as we know that s' is more than s so the ratio of s and s' will be less than 1
And hence here we can say that change in temperature of second pan will be less than 230 degree C which shows that final temperature of second pan will reach to lower temperature
So correct answer is
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