Answer:
I would say the answer is A... but I'm not so sure ....
Q=mcΔt
Q= 1kg * 800J/kg°C*4°C
Q= 3200J
Answer:
196000 N
Explanation:
The following data were obtained from the question:
Height (h) = 10 m
Area (A) = 2 m²
Force (F) =.?
Next, we shall determine the pressure in the tank.
This can be obtained as follow:
P = dgh
Where
P is the pressure.
d is the density of the liquid.
g is acceleration due to gravity
h is the height.
Height (h) = 10 m
Density (d) of water = 1000 kg/m³
Acceleration due to gravity (g) = 9.8 m/s²
Pressure (P) =...?
P = dgh
P = 1000 × 9.8 × 10
P = 98000 N/m²
Therefore, the pressure acting on the tank is 98000 N/m²
Finally, we shall determine the force of gravity acting on the column of water as follow:
Area (A) = 2 m²
Pressure (P) = 98000 N/m²
Force (F) =.?
Pressure (P) = Force (F) /Area (A)
P = F /A
98000 = F/ 2
Cross multiply
F = 98000 × 2
F = 196000 N
Therefore, the force of gravity acting on the column of water is 196000 N
