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3 years ago

A 1 kg puck sliding on a horizontal shuffleboard court is slowed to rest by 1 point

Physics

1 answer:

Citrus2011 [14]3 years ago

4 0

Answer:

miu = 0.31

Explanation:

The friction force is defined as the product of the normal force by the coefficient of friction.

$f=miu*N$

where:

f = friction force = 3 [N]

miu = friction coefficient

N = normal force [N]

The normal force on a horizontal surface can be calculated by means of the product of mass by gravity.

where:

m = mass = 1 [kg]

g = gravity acceleration = 9.81 [m/s²]

$N=m*g\\N=1*9.81$

$N= 9,81 [N]$

Now replacing in the equation above, we can find the friction coefficient.

$miu=3/9.81\\miu = 0.31$

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if a mass on a spring bobs up nad down completing 2 full cycles every section. WHat are the periouds and frequency of the mass

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Answer:

This question is incomplete

Explanation:

This question is incomplete because of the absence of the time taken to complete one full cycle.

Frequency (f) will be calculated first as

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3 years ago

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Brilliant_brown [7]

Answer:

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Explanation:

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3 years ago

A single slit of width 0.50 mm is illuminated with light of wavelength 500 nm, and a screen is placed 120 cm in front of the sli

Vaselesa [24]

Answer:

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Explanation:

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