4.20 mol Al would react completely with 4.20 x (1/2) = 2.10 mol Fe2O3, but there is not that much Fe2O3 present, so Fe2O3 is the limiting reactant. (1.75 mol Fe2O3) x (2/1) x ( 55.8452 g Fe/mol) = 195 g Fe 3 MgO + 2 H3PO4 → Mg3(PO4)2 + 3 H2O (15.0 g MgO) / (40.3045 g MgO/mol) = 0.37217 mol MgO (18.5 g H3PO4) / (97.9953 g H3PO4/mol) = 0.18878 mol H3PO4 0.18878 mol H3PO4 would react completely with 0.18878 x (3/2) = 0.28317 mole of MgO, but there is more MgO present than that, so MgO is in excess and H3PO4 is the limiting reactant. Now we must consider why the problem tells us "17.6g of Mg3(PO4)2 is obtained". The first possibility is that it's just there for the sake of confusion -- in which case ignore it and proceed this way: ((0.37217 mol MgO initially) - (0.28317 mole MgO reacted)) x (40.3045 g MgO/mol) = 3.59 g MgO left over However, if the amount of magnesium phosphate obtained is given because the reaction was stopped before it was complete, the amount obtained governs the amount reacted and the amount left over, so proceed this way: (17.6g Mg3(PO4)2) / (262.8581 g Mg3(PO4)2/mol) x (3/1) = 0.20087 mol MgO reacted ((0.37217 mol MgO initially) - (0.20087 mole MgO reacted)) x (40.3045 g MgO/mol) = 6.90 MgO left over
Explanation:
The given data is as follows.
T = 
= (11 + 273) K = 284 K, V = 45.0 L
m = 35 g
As molar mass of chlorine pentafluoride is 130.445 g/mol. Hence, number of moles of chlorine pentafluoride are as follows.
No. of moles = 
= 
= 0.268 mol
Now, using the ideal gas equation we will find the pressure as follows.
PV = nRT
P = 0.139 atm
Thus, we can conclude that pressure of chlorine pentafluoride gas in the given reaction vessel after the reaction is 0.139 atm.
The balanced chemical reaction would be written as follows:
CuCl2 + 2NaNO3 = Cu(NO3)2 + 2NaCl
This is an example of a double displacement type of reaction where the ions of the reactants displaces each other forming two new substances. Hope this answers the question.
Answer:
The pH of the solution is 1.66
Explanation:
Step 1: Data given
Number of moles HCl = 0.022 moles
Molar mass of HCl = 36.46 g/mol
Step 2: Calculate molarity of HCl
Molarity HCl = moles HCl / volume
Molarity HCl = 0.022 moles / 1 L = 0.022 M
[HCl] = [H+] = 0.022 M
Step 3: Calculate pH
pH = -log [H+]
pH = -log(0.022)
pH = 1.66
The pH of the solution is 1.66
