What type of chemical reaction is this CHA + 0,CO, + H2O

Silver (Ag) has two stable isotopes: 107Ag, 106.90 amu, and 109Ag, 108.90 amu. If the average atomic mass of silver is 107.87 am

inysia [295]

Answer:

The abundance of 107Ag is 51.5%.

The abundance of 109Ag is 48.5%.

Explanation:

The average atomic mass of silver can be expressed as:

107.87 = 106.90 * A1 + 108.90 * A2

Where A1 is the abundance of 107Ag and A2 of 109Ag.

Assuming those two isotopes are the only one stables, we can use the equation:

A1 + A2 = 1.0

So now we have a system of two equations with two unknowns, and what's left is algebra.

First we use the second equation to express A1 in terms of A2:

A1 = 1.0 - A2

We replace A1 in the first equation:

107.87 = 106.90 * A1 + 108.90 * A2

107.87 = 106.90 * (1.0-A2) + 108.90 * A2

107.87 = 106.90 - 106.90*A2 + 108.90*A2

107.87 = 106.90 + 2*A2

2*A2 = 0.97

A2 = 0.485

So the abundance of 109Ag is (0.485*100%) 48.5%.

We use the value of A2 to calculate A1 in the second equation:

A1 + A2 = 1.0

A1 + 0.485 = 1.0

A1 = 0.515

So the abundance of 107Ag is 51.5%.

3 0

2 years ago

Which statement below is not a premise of the Kinetic-molecular theory of gases?

zhuklara [117]

Answer:

d = all are premise of KMT.

Explanation:

A

Gas particles are extremely small and have relatively large distance between them.

B

Gas particles are continuously moving in random, straight-line motion as they are collide with each other and the container walls.

C

The average kinetic energy of gas particles is proportional to the temperature of gas.

All these are the premise of kinetic molecular theory. According to kinetic molecular theory, the particles pf gases are very small and randomly move in the available space. They move freely in straight line and colloid with each other and also the wall of container. This collision is elastic. As molecules strike with each other and walls of container their energy increases, and they gets warmer. So their kinetic energy is proportional to the temperature because mass of particle is constant.

4 0

2 years ago

Where are stars from in the spiral galaxy

zzz [600]

Stars form in the regions with the densest gas.

6 0

3 years ago

spontaneous redox reaction happens between zinc (Zn) and magnesium (Mg) in an electrochemical cell. (6 points) i. Use the reduct

aev [14]

Answer:

For (i): Magnesium is getting oxidized and zinc is getting reduced.

For (ii): The half reactions are given below.

For (iii): Magnesium will act as anode and zinc act as cathode.

Explanation:

For (i):

$E^o_{(Mg^{2+}/Mg)}=-2.37V\\E^o_{(Zn^{2+}/Zn)}=-0.76V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, zinc will always undergo reduction reaction will get reduced.

Magnesium will undergo oxidation reaction and will get oxidized.

For (ii):

Oxidation reaction is defined as the reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

$X\rightarrow X^{n+}+ne^-$

Reduction reaction is defined as the reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

$X^{n+}+ne^-\rightarrow X$

Oxidation half reaction: $Mg\rightarrow Mg^{2+}+2e^-$

Reduction half reaction: $Zn^{2+}+2e^-\rightarrow Zn$

For (iii):

Oxidation reaction always occurs on anode side and thus, magnesium is acting as anode.

Reduction reaction always occurs on cathode side and thus, zinc is acting as cathode.

3 0

3 years ago

A balloon is inflated with 2.42 L of helium at a temperature of 27 degrees celsius. Later, the volume of the balloon has changed

Setler79 [48]

Answer:

$P_1=100.3kPa$

Explanation:

Hello,

In this case, we use the combined law of gases which helps us to understand the changing pressure-volume-temperature behavior as shown below:

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

In this case, we are asked to compute the initial pressure before the ballon inflation, considering we must use absolute temperature units, therefore:

$P_1=\frac{P_2V_2T_1}{T_2V_1} =\frac{99.7kPa*2.37L*(27+273)K}{(19+273)K*2.42L} \\\\P_1=100.3kPa$

Best regards.

7 0

3 years ago

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