The satellite's rockets fire in 18.54 s
<h3>Further explanation</h3>
Given
F- Force = 550 N
I - impulse = 10,200 kg m/s
Required
Fire time
Solution
Impulse is defined is the product of the force with the time interval when the force is acting on the object.
Can be formulated :
I = F. Δt
Δt = I : F
Input the value :
Answer:
92.9%
Explanation:
You have been given the actual yield of the reaction. First, you need to find the theoretical yield of the reaction. To do this, you need to (1) convert grams Fe₂O₃ to moles Fe₂O₃ (via molar mass from periodic table values), then (2) convert moles Fe₂O₃ to moles Fe (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe to grams Fe (via molar mass).
Once you have found the theoretical yield, you need to use the percent yield equation to calculate the final answer. This number should have 3 sig figs to match the given values.
<u>(Step 1)</u>
Molar Mass (Fe₂O₃): 2(55.845 g/mol) + 3(15.998 g/mol)
Molar Mass (Fe₂O₃): 159.684 g/mol
1 Fe₂O₃(s) + 3 CO(g) ---> 2 Fe(s) + 3 CO₂(g)
Molar Mass (Fe): 55.845 g/mol
50.0 g Fe₂O₃ 1 mole 2 moles Fe 55.845 g
-------------------- x ------------------ x --------------------- x ---------------- = 35.0 g Fe
159.684 g 1 mole Fe₂O₃ 1 mole
<u>(Step 2)</u>
Actual Yield
Percent Yield = --------------------------- x 100%
Theoretical Yield
32.5 g Fe
Percent Yield = ---------------------- x 100% = 92.9%
35.0 g Fe
N2 + 3H2 ----> 2NH3
! mole of nitrogen reacts with 3 moles of hydrogen to give 2 moles of ammonia.
So by proportion number of moles NH3 obtained from 0.60 moles of N2 =
0.6 *2 = 1.2 moles Answer
500k value is equilibrium the answers is the value 250k
