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Scilla [17]
3 years ago
11

20 Points for urgency. Determine the [OH-] for the following. (Shown in image)

Chemistry
1 answer:
vredina [299]3 years ago
3 0
1.pOH+pH=14
pOH+1*10^=14
pOH=13.9999
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How many moles are in 9.25E24 formulas units of sodium acetate?
Lelu [443]

Answer:

<h2>15.37 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{9.25 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 15.365448...

We have the final answer as

<h3>15.37 moles</h3>

Hope this helps you

5 0
3 years ago
What is river capture​
abruzzese [7]
RIVER CAPTURE. *is when the powerful and energetic river cuts back through watershed by headward erosion cupturing another river's water. CONDITION FOR RIVER CAPTURE TO OCCUR. * steeper gradient on the energetic stream side of the watershed.Apr 6, 2019
6 0
3 years ago
1. Fill in the best answer for each of the following: a) ________________________ is the capacity to do work or to supply heat.
user100 [1]

Answer:

A. Energy

B. Chemical potential

C. Endothermic reaction

D.The law of conservation of mass

E. Transfers of energy

5 0
3 years ago
3. A compound was analyzed and found to contain 9.8 g of nitrogen, 0.70 g of
Nesterboy [21]

Answer:

HNO₃

Explanation:

Data given

Nitrogen = 9.8 g

Hydrogen =  0.70 g

Oxygen = 33.6 g

Empirical formula = ?

Solution:

Convert the masses to moles

For Nitrogen

Molar mass of N = 14 g/mol

                              no. of mole = mass in g / molar mass

Put value in above formula

                          no. of mole = 9.8 g/ 14 g/mol

                          no. of mole = 0.7

                           mole of N = 0.7 mol

For Hydrogen

Molar mass of H = 1 g/mol

                     no. of mole = mass in g / molar mass

Put value in above formula

                     no. of mole = 0.70 g/ 1 g/mol

                      no. of mole = 0.7

mole of H = 0.7 mol

For Oxygen

Molar mass of O = 16 g/mol

                       no. of mole = mass in g / molar mass

Put value in above formula

                       no. of mole = 33.6 g / 16 g/mol

                       no. of mole = 2.1

mole of O = 2.1 mol

Now we have values in moles as below

N = 0.7

H = 0.7

O = 2.1

Divide the all values on the smallest values to get whole number ratio

N = 0.7 / 0.7 = 1

H = 0.7 / 0.7 = 1

O = 2.1 / 0.7 = 3

So all have following values

N = 1

H = 1

O = 3

So the empirical formula will be HNO₃ i.e. all three atoms in simplest small ratio.

6 0
3 years ago
Use the name to write the formula for the following ionic compound: scandium (III) hydroxide
asambeis [7]

Answer:

.

Explanation:

.

6 0
2 years ago
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