Molar mass (NH₄)₂CO₃ = <span>96.09 g/mol
1 mole ---------> 96.09 g
0.500 moles ----> ?
0.500 * 96.09 = 48.045 g of </span><span>(NH₄)₂CO₃
hope this helps!
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The amount of W(OH)2 needed would be 448.126 g
<h3>Stoichiometric calculation</h3>
From the equation of the reaction:
W(OH)2 + 2 HCl → WCl2 + 2 H2O
The mole ratio of W(OH)2 to HCl is 1:2
Mole of 150g HCl = 150/36.461
= 4.11 moles
Equivalent mole of W(OH)2 = 4.11/2
= 2.06 moles
Mass of 2.06 moles W(OH)2 = 2.06 x 217.855
= 448.188g
More on stoichiometric calculations can be found here: brainly.com/question/8062886
Answer:
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Explanation: