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Dmitrij [34]
3 years ago
5

Mars can have bigger mountains than the Earth because it has a smaller mass and surface gravity.

Physics
2 answers:
aniked [119]3 years ago
6 0
It’s True I think ........
Katarina [22]3 years ago
5 0

Answer:

True

Explanation:

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What is the energy of a photon of ultraviolet radiation with a frequency of 4.4 × 1015 Hz? Planck’s constant is 6.63 × 10–34
Hunter-Best [27]

Answer:

2.9\cdot 10^{-18} J

Explanation:

The energy of a photon is given by:

E=hf

where

h is the Planck constant

f is the frequency of the photon

In this problem, we have:

h = 6.63\cdot 10^{-34} Js

f=4.4\cdot 10^{15} Hz is the frequency of the photon

Substituting into the equation, we find:

E=(6.63\cdot 10^{-34} Js)(4.4\cdot 10^{15} Hz)=2.9\cdot 10^{-18} J

4 0
3 years ago
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What is the theories of matter? Explain the first state of matter discovered (Stone Age) all the way to the end.
Ilia_Sergeevich [38]

Answer:

at the stone age people thought that every thing in the earth is made up of 5 elements they are:-air,earth,fire,sky and water

Explanation:

8 0
3 years ago
A resistor and an inductor are connected in series to a battery. The time constant for the circuit represents the time required
sattari [20]
E, 63% of the maximum current
5 0
4 years ago
Currently need help on this electric physics question, ive been stuck
Natali5045456 [20]

Answer:(1)=current (2)=force (3)=magnetic field (4)=reverse

Explanation:When there's a current in The coil. A force act on each side Of The coil. This is because the coil is in a magnetic field, the direction Of The spin would reverse

4 0
3 years ago
Car A and Car B approach each other
vagabundo [1.1K]

The original frequency of horn of Car A is 1071 Hz.

Explanation:

Doppler effect describes the change in the frequency of sound waves with respect to the observer. As the sound waves emitted from a source need to travel the air medium to reach observer, it will undergo loss in energy. So there will be change in its frequency compared to original frequency. Depending upon the direction of travel of source and observer the shifting of frequency will vary.

f'=\frac{v-v_{o} }{v-v_{s} } f

Here vo is the observer velocity and vs is the velocity of the source. So Vo = 15 m/s as car B is the observer and Vs = 35 m/s as car A is the source. And f is the frequency of sound wave at source that is car A.

Similarly, the doppler shift in frequency is the frequency of sound heard by car B which is f' = 1140 Hz. And v is the speed of sound that is v = 343 m/s

1140 = \frac{343-15}{343-35}*f= 1.0649 *f

f = 1140/1.0649= 1071 Hz.

Thus, the original frequency of horn of Car A is 1071 Hz.

3 0
4 years ago
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