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4 years ago

A(n) reverses the flow of current through an electric motor.

Physics

2 answers:

olya-2409 [2.1K]4 years ago

6 0

Answer:

Commutator is a ring which reverse the direction of current in AC circuit so that the coil connected to it will continuous to move in the same direction.

Explanation:

In motors there exist a coil which is rotated due to torque of magnetic field when current flow through it. Since AC current is used to run the motor so we know that AC current changes its direction after half cycle.

So here commutator plays an important role to reverse the direction of current after every half cycle so that the current goes in same direction always into the coil.

This will produce a constant direction torque on the coil so that it will rotate in same sense always.

So commutator role is to provide same direction current to the coil by reversing its direction after every half cycle

Andrews [41]4 years ago

4 0

Answer:

Commutator reverses the flow of current through an electric motor

Explanation:

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Sladkaya [172]

Answer:

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Explanation:

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4 years ago

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ahrayia [7]

Answer:

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Explanation:

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3 years ago

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Give some example acostic using "ELEMENTS"

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3 years ago

A worker drives a 0.554 kg spike into a rail tie with a 2.30 kg sledgehammer. The hammer hits the spike with a speed of 62.7 m/s

Goryan [66]

Answer:

Increase in total energy will be equal to the increase in the internal energy i.e $1130.246$ Joules

Explanation:

Given

Weight of sledge hammer $= 2.30$ kilogram

Speed of sledge hammer $= 62.7$ meter per second

Kinetic energy is equal to half the product of mass and velocity square

$K E = \frac{1}{2} mv^2$

Substituting the value of mass and velocity, we get -

$KE = 0.5 * 2.30 * 62.7^2\\KE = 4520.9835$

It is given that one fourth of the energy is converted into internal energy

One fourth of kinetic energy is equal to

$\frac{1}{4} * 4520.9835\\= 1130.246$

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3 years ago

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The inner and outer surfaces of a cell membrane carry a negative and positive charge, respectively. Because of these charges, a

sertanlavr [38]

Answer:

Electric field, E = $6.36\times 10^{6}\ V/m$

Explanation:

Given that,

The potential difference across the membrane, $\Delta V=0.063\ V$

The thickness of the membrane is, $\Delta x=9.9\times 10^{-9}\ m$

We need to find the magnitude of the electric field in the membrane. We know that the relation between electric field and electric potential is given by :

$E=\dfrac{-\Delta V}{\Delta x}\\\\E=\dfrac{0.063\ V}{9.9\times 10^{-9}\ m}\\\\E=6.36\times 10^{6}\ V/m$

So, the magnitude of the electric field in the membrane is $6.36\times 10^{6}\ V/m$ .

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4 years ago