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cestrela7 [59]
3 years ago
6

Rearrange the formula F=ma, and solve for the variable (a)

Physics
1 answer:
jeyben [28]3 years ago
7 0

Answer:

a = F/m

Explanation:

So we have to isolate a, in order to do this we need to move m to the other side, and we do that by diving both sides by m, resulting in a = F/m

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Determine the internal resistance of the capacitor.
11Alexandr11 [23.1K]

Answer:

The equivalent series resistance of a capacitor is the internal resistance that appears in series with the capacitance of the device. Almost all capacitors exhibit this property at varying degrees depending on the construction, dielectric materials, quality, and reliability of the capacitor.

Explanation:

Hope this helps

7 0
2 years ago
Which action can humans take to reduce wave erosion?
mezya [45]

The action that  humans can take to reduce wave erosion is to build breakwaters in the ocean.

<h3>What is erosion?</h3>

The term erosion has to do with the washing away of top soil either by water or by wind. The control of erosion is a very important soil conservation effort.

Hence, the action that  humans can take to reduce wave erosion is to build breakwaters in the ocean.

Learn more about erosion:brainly.com/question/3852201?

#SPJ1

3 0
2 years ago
Calculate the energy of a photon having a wavelength in thefollowing ranges.(a) microwave, with λ = 50.00 cmeV(b) visible, with
IgorLugansk [536]

(a) 2.5\cdot 10^{-6}eV

The energy of a photon is given by:

E=\frac{hc}{\lambda}

where

h=6.63\cdot 10^{-34}Js is the Planck constant

c=3\cdot 10^8 m/s is the speed of light

\lambda is the wavelength

For the microwave photon,

\lambda=50.00 cm = 0.50 m

So the energy is

E=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{0.50 m}=4.0\cdot 10^{-25} J

And converting into electronvolts,

E=\frac{4.0\cdot 10^{-25}J}{1.6\cdot 10^{-19} J/eV}=2.5\cdot 10^{-6}eV

(b) 2.5 eV

For the energy of the photon, we can use the same formula:

E=\frac{hc}{\lambda}

For the visible light photon,

\lambda=500 nm = 5 \cdot 10^{-7}m

So the energy is

E=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{5\cdot 10^{-7} m}=4.0\cdot 10^{-19} J

And converting into electronvolts,

E=\frac{4.0\cdot 10^{-19}J}{1.6\cdot 10^{-19} J/eV}=2.5 eV

(c) 2500 eV

For the energy of the photon, we can use the same formula:

E=\frac{hc}{\lambda}

For the x-ray photon,

\lambda=0.5 nm = 5 \cdot 10^{-10}m

So the energy is

E=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{5\cdot 10^{-10} m}=4.0\cdot 10^{-16} J

And converting into electronvolts,

E=\frac{4.0\cdot 10^{-16}J}{1.6\cdot 10^{-19} J/eV}=2500 eV

6 0
3 years ago
Will get Brainlest 5 star and heart looking for someone who knows 7 grd science flvs work dm and friend
Makovka662 [10]
ANSWER:
C

EXPLANTION:
The earths crust is the toppest layer of Earth, so that elimates option A and B.

FUN FACT:
Earth is Mostly Iron, Oxygen and Silicon

I’m so sorry if this is wrong, but I hoped help.
Have a nice day :3
3 0
3 years ago
The coefficients of friction between the 20-kg crate and the inclined surface are µ,8 = 0.24 and J.lk = 0.22. If the crate start
Yanka [14]

Answer:5.60 m/s

Explanation:

Given

Coefficient of static friction \mu _s=0.24

Coefficient of kinetic friction \mu _k=0.22

mass of crate m=20\ kg

Force applied F=200\ N

maximum static Friction F_s=\mu _sN

N=mg

F_s=0.24\times 20\times 9.8

F_s=47.04\ N

thus applied force is greater than Static friction therefore kinetic friction will come into play

F_k=\mu _kN

F_k=0.22\times 20\times 9.8=43.12\ N

net Force on crate F-F_k=ma

a=\frac{200-43.12}{20}=7.84\ m/s^2

Magnitude of velocity can be obtained by using

v^2-u^2=2as

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

here initial velocity is zero as crate start from rest

v^2-0=2\times 7.84\times 2

v=\sqrt{31.37}

v=5.60\ m/s                                          

7 0
4 years ago
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