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EastWind [94]
3 years ago
5

How far up a wall will an 11 meter ladder reach, if the foot of the ladder must be 4 meters from the base of the wall? Round to

the nearest hundredth.
Mathematics
2 answers:
tatiyna3 years ago
7 0

Answer with explanation:

Length of ladder= 11 meter

Distance from foot of ladder to base of wall = 4 meter

Let height of Wall upto which Ladder reach = h meter

By using Pythagorean theorem

⇒(Length of ladder)²=(Height of Wall upto which Ladder reach)² + ( Distance from foot of ladder to base of wall)²

⇒(11)²=(Height of Wall upto which Ladder reach)²+4²

Subtracting 16 from both sides

⇒121 -16 = (Height of Wall upto which Ladder reach)²

⇒105 = (Height of Wall upto which Ladder reach)²

⇒ Height of Wall upto which Ladder reach

                           =\sqrt{105}\\\\=10.2469\\\\=10.25 \text{meter}                            

seraphim [82]3 years ago
3 0
Use pythagorean theorem. 11m is the hypotenuse, while 4m is one of the legs. the wall should create a right angle with the ground which will allow for the pythagorean theorem. The height of where the ladder reaches will be named x.
x=<span>√11^2-4^2=10.25m.</span>
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Answer:

1.1

Step-by-step explanation:

1 in probability means always so anything greater than 1 is meaningless

6 0
3 years ago
Simplify 4^3•4^5.<br> help asap !
Julli [10]

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D

Step-by-step explanation:

when there are exponents with same bases multiplied by each other, keep the base and add the exponents

4^(3)+4^(5)=4^8

4^8 is D in this question

7 0
3 years ago
Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.
o-na [289]

Answer: \text{Length of AG=}\frac{2\sqrt{63}}{3}

Explanation:  

Please follow the diagram in attachment.  

As we know median from vertex C to hypotenuse is CM  

\therefore CM=\frac{1}{2}AB

We are given length of CG=4  

Median divide by centroid 2:1  

CG:GM=2:1  

Where, CG=4

\therefore GM=2 ft

Length of CM=4+2= 6 ft  

\therefore CM=\frac{1}{2}AB\Rightarrow AB=12

In \triangle ABC, \angle C=90^0

Using trigonometry ratio identities  

AC=AB\sin 30^0\Rightarrow AC=6 ft

BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3} ft  

CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3} ft

In \triangle CAN, \angle C=90^0  

Using pythagoreous theorem  

AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}

Length of AG=2/3 AN

\text{Length of AG=}\frac{2\sqrt{63}}{3} ft


5 0
3 years ago
7/8y + 1/2 = 1 1/5<br><br> Solve for y.
abruzzese [7]

Answer:

y = 4/5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

7/8y + 1/2 = 1 1/5

<u>Step 2: Solve for </u><em><u>y</u></em>

  1. Convert to improper fraction:                                                                          7/8y + 1/2 = 6/5
  2. [Subtraction Property of Equality] Subtract 1/2 on both sides:                       7/8y = 7/10
  3. [Division Property of Equality] Divide 7/8 on both sides:                              y = 4/5
3 0
3 years ago
Solve the equation -15=a/5 <br> A=-3<br> A=-20<br> A=-10<br> A=-75
agasfer [191]

To solve any equation, you do whatever you need to do 
to wind up with the unknown quantity all alone on one side.
BUT ... whatever you do to one side of the equation, you must
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Here, we have the
he original equation:           -15  =  a/5

Multiply each side by 5 :     -75  =  a

and bada-bing, THERE's the solution !
4 0
3 years ago
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